∫ (2,1) root sign (4-x ^ 2) / x ^ 2 DX PS: the root sign is (4-x ^ 2) and the denominator is x ^ 2 I can't do it. Thank you for your advice

∫ (2,1) root sign (4-x ^ 2) / x ^ 2 DX PS: the root sign is (4-x ^ 2) and the denominator is x ^ 2 I can't do it. Thank you for your advice

Exchange method,
Let x = 2cost, DX = - 2sintdt
x=1,t=π/3,x=2,t=0

When calculating the arc length of a curve in polar coordinates, where is the error when the arc length element is DS = R (θ) d θ?

Calculation of arc length of curve in polar coordinate system let the equation of curve be r = R (θ) why can't arc differential be DS = R (θ) d θ

If l is a line segment from a (1,0) to B (- 1,2), then the curve integral ∫ L (x + y) ds

The equation of a (1,0) to B (- 1,2) is y = - x + 1, X: - 1 -- > 1
Substituting curve integral into definite integral, we get the following result:
∫L(x+y)ds
=∫[-1-->1] (x+(-x+1))*√(1+1)dx
=∫[-1-->1] √2 dx
=2√2