Let d be the square of the circle x + the area of the bungalow of Y, then the double integral 2dxdy =? The answer is 18pi~

Let d be the square of the circle x + the area of the bungalow of Y, then the double integral 2dxdy =? The answer is 18pi~


The area of ∫ ∫ 2dxdy = 2 * D
If the answer is 18 PI, then D is the square of the circle x + the square of y = 9



High number surface integral: calculate ∫ (x + y) e ^ (x ^ 2 + y ^ 2) ds, where l is the fan-shaped boundary bounded by circular arc y = √ (a ^ 2-x ^) and straight line y = x and y = - X


L is parameterized by y = √ (A & # 178; - X & # 178;) and y = x and y = - X: T: - π / 4 → π / 4x = acost, y = asintdx = - asintdt, Dy = acostdtds = ADT ∫ L (x + y) e ^ (X & # 178; + Y & # 178;) ds = ∫ (- π / 4, π / 4) (acost + asint) e



Advanced number problem: y ^ 2F (x) + XF (y) = x ^ 2 (^ for square), f (x) differentiable, find dy


Differential on both sides:
f(x)×2ydy+y^2×f'(x)dx+f(y)dx+xf'(y)dy=2xdx
dy=[2x-f(y)-f'(x)y^2]dx/[2yf(x)+xf'(y)]



Using the law of lobita to get the derivative LIM (x → pi / 2-0): (TaNx) ^ (2x PI) pi = 3.1415926


LIM (x → π / 2-0) (TaNx) ^ (2x - π) = e ^ LIM (x → π / 2-0) (2x - π) ln (TaNx) = e ^ LIM (x → π / 2-0) ln (TaNx) / [1 / (2x - π)] ∞ / ∞ type, using the law of Robida = e ^ LIM (x → π / 2-0) 1 / (TaNx) * sec ^ 2x / [- 2 / (2x - π) ^ 2] = e ^ LIM (x → π / 2-0) - (2x - π)