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The volume formula of ellipse
4/3πabc
Any liquid level volume calculation formula of horizontal oval oil tank!
45 meters, 5.1 meters long and 2.08 meters wide. The current liquid level is 0.87 meters. If the liquid level is 1 meter? 0.5 meters, 0.85 meters and 0.92 meters? What formula should be used to calculate?
The cross section of oil is a bow
Let the arc of arc AB be arc AB, then:
When the arc AB is a inferior arc, then s arc = s sector - s △ AOB (a, B are the ends of the arc, O is the center of the circle)
When the arc AB is a semicircle, then s arc = s sector = 1 / 2S circle = 1 / 2 × π R ^ 2
When the arc AB is a superior arc, then s arc = s sector + s △ AOB (A and B are the ends of the arc, O is the center of the circle)
The calculation formulas are as follows:
S＝nπR^2÷360－ah÷2
S＝πR^2/2
S＝nπR^2÷360+ah÷2
After obtaining the bow area, multiply it by the length of 5.1 meters
T is the formula for calculating the volume of an elliptical object TT * AB * H
Long radius * short radius * Pai * height of ellipse
If the vertex of the parabola y = - x2 + 8x-12 is p, and the two intersections with the X axis are C and D, then the area of △ PCD is______ ．
Because the vertex of the parabola y = AX2 + BX + C (- B2A, 4ac − b24a), the vertex of the parabola y = - x2 + 8x-12 is p (4, 4). When y = 0, - x2 + 8x-12 = 0, the solution is x = 2 or x = 6, so the coordinates of the two intersections C and D with the X axis are (2, 0), (6, 0). So the area of △ PCD is 8
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