Is the trajectory of horizontal throwing a parabola! Is the trajectory of horizontal projectile a parabola? But its trajectory is only half of that of parabola (quadratic function with opening downward)?

Is the trajectory of horizontal throwing a parabola! Is the trajectory of horizontal projectile a parabola? But its trajectory is only half of that of parabola (quadratic function with opening downward)?

Answer: Yes. We can understand that if you say that the trajectory of a horizontal throw is a parabola, then no matter how you throw it, the trajectory is not a parabola, because the parabola has no endpoint, and its two sides are infinitely extended. No matter how you throw it, there will be an endpoint, that is, the point of your parabola. So the trajectory of a horizontal throw is a parabola

How to verify that the trajectory of horizontal throwing motion is a parabola?

Establish the coordinate system, take the throwing direction as the x-axis positive direction, the vertical downward direction as the y-direction, the horizontal throwing velocity V, time t,
Falling height h,
Horizontal square x = VT, t = x / V
h=(gt^2)/2,
h=(g/2)*(x/v)^2=[g/(2v^2)]*x^2
g. V is a known constant, so the above formula is a quadratic function of X, which is a parabola

It is proved that the trajectory of an object in horizontal motion is a parabola

This paper lists the displacement time function relation equation of the object's horizontal throwing motion: the vertical direction: H = 1 / 2GT ^ 2, the horizontal direction: VT = x, two simultaneous expressions: H = GX ^ 2 / 2V ^ 2, which is obviously a parabolic equation

The trajectory of horizontal throwing motion is a parabola. How to deduce it?

Displacement parameter equation
x=vot (1)
y=(1/2)gt^2 (2)
Substituting (1) t = x / V0 into (2)
y=(1/2)g(x/v0)^2 =(g/2v0^2)x^2