![](data:image/svg+xml;utf8,<svg xmlns="http://www.w3.org/2000/svg" xmlns:xlink="http://www.w3.org/1999/xlink" viewBox="0 0 72 71" width="72"></svg>)
The range of the image of the function y = LG (2 + x) + LG (2-x) with respect to the symmetric function f (x) = LG (x2-2x + 1)
Y = LG (2 + x) + LG (2-x) = LG (4-x & # 178;), which is even function, and the symmetry axis is Y axis
The logarithmic function is an increasing function, and the value range of F (x) = LG (x-1) &# 178;, (x-1) &# 178; is (0, ∞), and the value range of F (x) is (- ∞, + ∞)
Given the function f (x) = x square + MX + 4, G (x) = x square + 2x-2m
(1) If at least one of the equations f (x) = 0 and G (x) = 0 has a real root, the range of real number m is obtained
(2) If the equation g (x) = 0 has a real root in the interval (- ∞, - 2) and (- 2,1), the range of real root m is obtained
1) Delta1 = m ^ 2-16 - 4 m
RELATED INFORMATIONS
- 1. It is known that the odd function f (x) = - X's square + 2x (x > 0) 0 (x = 0) x's Square = MX (x)
- 2. Draw the image of function y = 1 / 2x + 1 in the given rectangular coordinate system (fill in the following table first, and then draw the line of points) x=-3 y=?…… x=3 y=?
- 3. Given the function f (x) = 2Sin (x + π / 3) - 2sinx, X belongs to - π / 2,0 (1) If cosx = √ 3 / 3, find the value of function f (x) (2) Finding the range of function f (x) I'm in a hurry
- 4. It is proved that the periods of F (x + a) = - f (x) and f (x + a) = 1 / F (x) are 2A The approximate step is f (x + 2a) = f [(x + a) + a] = - f (x + a) = f (x), so f (x + 2a) = f (x), so the period is 2A F (x + 2a) = f [(x + a) + a] = 1 / F (x + a) = f (x), so f (x + 2a) = f (x), so the period is 2A These are the teacher's steps, but I can't understand them now,
- 5. It is known that f (x) is an even function defined on R, and the image of y = f (x) is symmetric with respect to the line x = 2. It is proved that f (x) is a periodic function
- 6. We know that vector a = (cosx, SiNx), vector b = (cosy, siny), | A-B | = 2 * & 5 / 5, 1. Find the value of COS (X-Y) 2. If 0 Please write the specific steps (O & # 180; &;'O) ぉ (O & # 180; Д'o) は (O & # 180; ω'o) ょ
- 7. sin（x-y）cosy+cos（x-y）siny=?
- 8. A brief and detailed process of transforming trigonometric function sin (X-Y) cosy + cos (X-Y) siny
- 9. If the maximum value of quadratic function f (x) = x2 + 4x + 6 on [M, 0] is 6 and the minimum value is 2, then the value range of real number m is______ ．
- 10. Is f (x) = cos (x + π) even function
- 11. It is known that the function f (x) defined on [0,1] satisfies the following three conditions simultaneously It is known that the function f (x) defined on [0,1] satisfies the following condition: when x1 ≥ 0, X2 ≥ 0, X1 + x2 ≤ 1, f (x1 + x2) ≥ f (x1) + F (x2) always holds, and whether the function g (x) = 2 ^ X - 1 satisfies this condition in the interval [0.1]
- 12. The function f (x) is an even function on R, and is a decreasing function on (- 00,0). Compare the size of F (- 7 / 8) and f (2a ^ 2-A + 1)
- 13. When x belongs to R, the function y = f (x) satisfies f (2002 + x) + F (2004 + x) = f (2003 + x), and f (1) = Lg3 / 2, f (2) = LG15, then f (2007) =?
- 14. Given the function f (x) = x ^ 2-cosx, for any x1, X2 on [- π / 2, π / 2], we have the following conditions: A.x1>x2 B.x1^2>x2^2 C.|x1|>x2 The condition that f (x1) > F (x2) is constant is B. why
- 15. Known sequence {an}, {BN} satisfy: A1 = 1 / 4, an + BN = 1, BN + 1 = BN / 1-an ^ 2. Find {BN} general term formula
- 16. Given function, f (x) = 2x + 1, G (x0 = x), (x belongs to R, sequence, {an}, {BN} satisfies A1 = 1, an = f (BN) = g (BN + 1) to find the general term formula of sequence {an}
- 17. It is proved that the sequence LG (1 + an) is an equal ratio sequence It's known
- 18. Given that the image of the function y = MX - (4m-3) (M is a constant) passes through the origin, what is the value of M
- 19. We know that the image of the first-order function passes through the point P (2,3), and the image and the y-axis intersect at the point m, and the distance from the point m to the origin is equal to 5. Find the expression of the first-order function and draw the qualified image
- 20. If the image of the linear function y = MX - (M-3) passes through the origin, then the value of M is