If the image of the linear function y = MX - (M-3) passes through the origin, then the value of M is

If the image of the linear function y = MX - (M-3) passes through the origin, then the value of M is


Because the first-order function K cannot be equal to 0, so m is not equal to 0, and because the image passes through the origin, it is substituted. When x = 0, y = 0
So, M-3 = 0, so m = 3, and M is not equal to 0



The first-order function y = MX + n when m n is the value, the function image passes through the origin
Why is the intersection of the image and the y-axis above the x-axis when the value of m n
What is the value of m n when the image passes through the second, third and fourth quadrant


M is a real number, n = 0
M is a real number, n > 0
m



Given that the image of the first-order function passes through the point P (2,3) and the distance between the image and the y-axis intersects the point m, the distance from the point m to the origin is equal to 5, find the relationship of the first-order function and draw the qualified image


Let y = KX + B
Because the distance from the origin of M is 5, M is on the y-axis
So m (0,5) or (0, - 5)
Because the image is over P (2,3)
If M (0,5)
b=5
2k+b=3
k=-1
b=5
y=-x+5
If M (0, - 5)
b=-5
k=4
y=4x-5
So y = - x + 5 or y = 4x-5



Given that the graph of a first-order function passes through the point P (2,3), and the intersection of the image and the y-axis with the point m, the distance from the point m to the origin is equal to 5, find the relationship of the first-order function
And draw a qualified image


There are two possibilities for the coordinates of M (0, - 5), (0,5)
When m coordinate is (0, - 5), y = 4x-5 can be calculated by y = KX + B combined with P (2,3)
When m coordinate is (0,5), y = - x + 5 can be calculated as above
The linear function is y = 4x-5 or y = - x + 5