![](data:image/svg+xml;utf8,<svg xmlns="http://www.w3.org/2000/svg" xmlns:xlink="http://www.w3.org/1999/xlink" viewBox="0 0 72 71" width="72"></svg>)
If the image of the function y = MX - (4m-4) passes through the origin, then M=______ Y increases with the increase of X______ ．
When the image of ∵ y = MX - (4m-4) passes through the origin, ∵ (4m-4) = 0, the solution is m = 1, ∵ y = x, ∵ y increases with the increase of X
If the image of the function y = MX - (4m-4) passes through the origin, then M=______ Y increases with the increase of X______ ．
When the image of ∵ y = MX - (4m-4) passes through the origin, ∵ (4m-4) = 0, the solution is m = 1, ∵ y = x, ∵ y increases with the increase of X
If the image of a linear function y = MX + (m ^ 2-3m) passes through the origin, then M=
Since the image of y = MX + (m ^ 2-3m) passes through the origin, there is a
M ^ 2-3m = 0, M = 0 or M = 3
Obviously, when m = 3, the function y = 3x satisfies the condition
Because when m = 0, the function is y = 0, although it also passes through the origin, according to the definition of a function,
Y = KX + B (K ≠ 0) (k is not equal to 0, and K, B are constants), we know that M = 0 does not meet the condition
So m = 3
If the graph of a linear function y = MX - (m-2) passes through the origin, then M=_____
Take x = 0, y = 0 into a function to get
0＝m*0－（m-2)
So m = 2
RELATED INFORMATIONS
- 1. If the image of the linear function y = MX - (M-3) passes through the origin, then the value of M is
- 2. We know that the image of the first-order function passes through the point P (2,3), and the image and the y-axis intersect at the point m, and the distance from the point m to the origin is equal to 5. Find the expression of the first-order function and draw the qualified image
- 3. Given that the image of the function y = MX - (4m-3) (M is a constant) passes through the origin, what is the value of M
- 4. It is proved that the sequence LG (1 + an) is an equal ratio sequence It's known
- 5. Given function, f (x) = 2x + 1, G (x0 = x), (x belongs to R, sequence, {an}, {BN} satisfies A1 = 1, an = f (BN) = g (BN + 1) to find the general term formula of sequence {an}
- 6. Known sequence {an}, {BN} satisfy: A1 = 1 / 4, an + BN = 1, BN + 1 = BN / 1-an ^ 2. Find {BN} general term formula
- 7. Given the function f (x) = x ^ 2-cosx, for any x1, X2 on [- π / 2, π / 2], we have the following conditions: A.x1>x2 B.x1^2>x2^2 C.|x1|>x2 The condition that f (x1) > F (x2) is constant is B. why
- 8. When x belongs to R, the function y = f (x) satisfies f (2002 + x) + F (2004 + x) = f (2003 + x), and f (1) = Lg3 / 2, f (2) = LG15, then f (2007) =?
- 9. The function f (x) is an even function on R, and is a decreasing function on (- 00,0). Compare the size of F (- 7 / 8) and f (2a ^ 2-A + 1)
- 10. It is known that the function f (x) defined on [0,1] satisfies the following three conditions simultaneously It is known that the function f (x) defined on [0,1] satisfies the following condition: when x1 ≥ 0, X2 ≥ 0, X1 + x2 ≤ 1, f (x1 + x2) ≥ f (x1) + F (x2) always holds, and whether the function g (x) = 2 ^ X - 1 satisfies this condition in the interval [0.1]
- 11. (1) It is known that the image of the first-order function is parallel to the image of the positive scale function y = - 2 / 3x, and the value of the function is positive when it passes through points m (0,4), (2) x? And (3) if y is greater than or equal to - 1 and less than 2, then the value range of X is?
- 12. What is the vertex coordinate of the image of quadratic function y = (x - |) & # - 2?
- 13. An analytic formula for finding the minimum value g (a) of quadratic function f (x) = x2-2 (2a-1) x + 5a2-4a2 + 2 on [0,1] An analytic formula for finding the minimum value g (a) of quadratic function f (x) = x2-2 (2a-1) x + 5a2-4a + 2 on [0,1]
- 14. Given the quadratic function f (x) = x & # 178; - 4x, its domain of definition is d. if d = [a, a + 2], find the minimum value of function f (x)
- 15. The quadratic function y = - 3x draws an image
- 16. If we know the vertex 1, - 2 of quadratic function and pass through point 1. - 2, then the analytic expression is
- 17. Quadratic function for vertex coordinates formula for vertex coordinates, no C how to do? y=x2+8x This form is not given to C What about 4ac and C?
- 18. The negation of the proposition "the image of the original function and the inverse function is symmetric with respect to y = x" is______ ．
- 19. How many degrees does the minute hand of the clock rotate from 4 o'clock to coincide with the hour hand
- 20. When the minute hand of the clock rotates clockwise from 4 o'clock, how many degrees does the minute hand coincide with the hour hand? The answer is 130 / 10 / 11 degrees!