An analytic formula for finding the minimum value g (a) of quadratic function f (x) = x2-2 (2a-1) x + 5a2-4a2 + 2 on [0,1] An analytic formula for finding the minimum value g (a) of quadratic function f (x) = x2-2 (2a-1) x + 5a2-4a + 2 on [0,1]

An analytic formula for finding the minimum value g (a) of quadratic function f (x) = x2-2 (2a-1) x + 5a2-4a2 + 2 on [0,1] An analytic formula for finding the minimum value g (a) of quadratic function f (x) = x2-2 (2a-1) x + 5a2-4a + 2 on [0,1]

The midpoint coordinates of quadratic function f (x) = x2-2 (2a-1) x + 5a2-4a + 2 on [0,1] are as follows:
X=(0+1)/2=1/2.
The axis of symmetry of F (x) is x = 2A + 1, and the opening of parabola is upward,
Discussion:
1) When 2a-1 ≤ 0, a ≤ 1 / 2, when x = 0, f (x) is the minimum,
g(a)=5a^2-4a+2,(a≤1/2).
2) When 0

What is the vertex coordinate of the quadratic function y = - (x-1) &# + 3 image?

Vertex coordinates are (1,3)

Quadratic function y = 3 (x + 2) ² - 1 the vertex coordinates of the image are?

Y = 3 (x + 2) & # - 1 the vertex coordinates of the image are (- 2, - 1)