![](data:image/svg+xml;utf8,<svg xmlns="http://www.w3.org/2000/svg" xmlns:xlink="http://www.w3.org/1999/xlink" viewBox="0 0 72 71" width="72"></svg>)
What is the vertex coordinate of the image of quadratic function y = (x - |) & # - 2?
1.-2
What are the vertex coordinates of the quadratic function y = - (x-1) &# + 3 image
I kind of forgot,
,
3Q
What you write is the vertex type
Vertex coordinates (1,3)
Vertex formula: y = a (X-H) ^ 2 + K vertex coordinates: (h, K)
As shown in the figure, the vertices a and C of the trapezoidal aobc are on the inverse scale function image, OA ‖ BC, the upper bottom edge OA is on the straight line y = x, and the lower bottom edge BC intersects the X axis on the Y axis of E (2,0)
At point B, and the ordinate of C is 1
According to the meaning of the problem, the analytic expression of BC is y = X-2, and the analytic expression of inverse proportion function is y = 3 / x, so x = 3 / X,
The solution is x = root 3 (x = - root 3 is not suitable for the subject), and y = root 3, that is, the coordinate of point a is (root 3, root 3)
The image of the linear function y = - 3x + 5 is a straight line passing through the point (0,) and parallel to the image of the positive scale function y = ()
Analysis
Set X = 0
Substituting equation y = 5
So after (0.5)
Parallel lines K are equal
therefore
Positive proportional straight line y = - 3x
Hope to help you
Learning progress o (∩)_ Thank you
RELATED INFORMATIONS
- 1. (1) It is known that the image of the first-order function is parallel to the image of the positive scale function y = - 2 / 3x, and the value of the function is positive when it passes through points m (0,4), (2) x? And (3) if y is greater than or equal to - 1 and less than 2, then the value range of X is?
- 2. If the image of the function y = MX - (4m-4) passes through the origin, then M=______ Y increases with the increase of X______ ．
- 3. If the image of the linear function y = MX - (M-3) passes through the origin, then the value of M is
- 4. We know that the image of the first-order function passes through the point P (2,3), and the image and the y-axis intersect at the point m, and the distance from the point m to the origin is equal to 5. Find the expression of the first-order function and draw the qualified image
- 5. Given that the image of the function y = MX - (4m-3) (M is a constant) passes through the origin, what is the value of M
- 6. It is proved that the sequence LG (1 + an) is an equal ratio sequence It's known
- 7. Given function, f (x) = 2x + 1, G (x0 = x), (x belongs to R, sequence, {an}, {BN} satisfies A1 = 1, an = f (BN) = g (BN + 1) to find the general term formula of sequence {an}
- 8. Known sequence {an}, {BN} satisfy: A1 = 1 / 4, an + BN = 1, BN + 1 = BN / 1-an ^ 2. Find {BN} general term formula
- 9. Given the function f (x) = x ^ 2-cosx, for any x1, X2 on [- π / 2, π / 2], we have the following conditions: A.x1>x2 B.x1^2>x2^2 C.|x1|>x2 The condition that f (x1) > F (x2) is constant is B. why
- 10. When x belongs to R, the function y = f (x) satisfies f (2002 + x) + F (2004 + x) = f (2003 + x), and f (1) = Lg3 / 2, f (2) = LG15, then f (2007) =?
- 11. An analytic formula for finding the minimum value g (a) of quadratic function f (x) = x2-2 (2a-1) x + 5a2-4a2 + 2 on [0,1] An analytic formula for finding the minimum value g (a) of quadratic function f (x) = x2-2 (2a-1) x + 5a2-4a + 2 on [0,1]
- 12. Given the quadratic function f (x) = x & # 178; - 4x, its domain of definition is d. if d = [a, a + 2], find the minimum value of function f (x)
- 13. The quadratic function y = - 3x draws an image
- 14. If we know the vertex 1, - 2 of quadratic function and pass through point 1. - 2, then the analytic expression is
- 15. Quadratic function for vertex coordinates formula for vertex coordinates, no C how to do? y=x2+8x This form is not given to C What about 4ac and C?
- 16. The negation of the proposition "the image of the original function and the inverse function is symmetric with respect to y = x" is______ ．
- 17. How many degrees does the minute hand of the clock rotate from 4 o'clock to coincide with the hour hand
- 18. When the minute hand of the clock rotates clockwise from 4 o'clock, how many degrees does the minute hand coincide with the hour hand? The answer is 130 / 10 / 11 degrees!
- 19. From seven o'clock to (), the clock hand rotates 30 degrees clockwise around o point, and the minute hand rotates () degrees clockwise around o point
- 20. How many degrees clockwise can the minute hand of the clock coincide with the hour hand from the 4 o'clock position?