One variable quadratic equation test questions 1. It is known that a is a root of the univariate quadratic equation x2-3x + M = 0 about X, and - A is the univariate quadratic equation x2 + 3x-m = 0 about X. try to find the value of A 2. If we know that the equation (K2 + 2) x2 + (5-K) x = 1-3kx2 is a univariate quadratic equation about X, can you find the value of K? 3 (x2 + 3x + 4) (x2 + 3x + 5) = 6 It is known that m.n is the two real number roots of the equation X2 - (P-2) x + 1 = 0 about X. find the value of the algebraic formula (M2 + MP + 1) (N2 + NP + 1)

One variable quadratic equation test questions 1. It is known that a is a root of the univariate quadratic equation x2-3x + M = 0 about X, and - A is the univariate quadratic equation x2 + 3x-m = 0 about X. try to find the value of A 2. If we know that the equation (K2 + 2) x2 + (5-K) x = 1-3kx2 is a univariate quadratic equation about X, can you find the value of K? 3 (x2 + 3x + 4) (x2 + 3x + 5) = 6 It is known that m.n is the two real number roots of the equation X2 - (P-2) x + 1 = 0 about X. find the value of the algebraic formula (M2 + MP + 1) (N2 + NP + 1)

1. Substituting a into the equation x2-3x + M = 0, a2-3a + M = 0 is obtained;
Substituting - a into the equation x2 + 3x-m = 0, (- a) 2 + 3 * (- a) - M = 0 = = > a2-3a-m = 0
So m = 0, so a2-3a = 0, so a = 3. A = 0
a=3
2. The equation (K2 + 2) x2 + (5-K) x = 1-3kx2 is a quadratic equation of one variable about X
So K2 + 2 + 3K ≠ 0,
So K ≠ - 1, K ≠ - 2
3. Through observation, X2 + 3x + 4 is always smaller than x2 + 3x + 5 by "1", so x2 + 3x + 4 = 2, X2 + 3x + 5 = 3, or x2 + 3x + 4 = - 3, X2 + 3x + 5 = - 2 (these two equations have no real roots)
So, x = - 1, or x = - 2,
4. M. n is the two real roots of the equation X2 - (P-2) x + 1 = 0 about X,
So there are: M2 - (P-2) m + 1 = 0 and N2 - (P-2) n + 1 = 0
So: M2 MP + 2m + 1 = 0 and N2 NP + 2n + 1 = 0
M2 + MP + 1 = 2mp-2m and N2 + NP + 1 = 2np-2n
So: (M2 + MP + 1) (N2 + NP + 1) = (2mp-2m) * (2np-2n) = 4Mn (p-1) ^ 2
Because Mn = 1, so: (M2 + MP + 1) (N2 + NP + 1) = 4 (p-1) ^ 2

Who has the exercises of quadratic equation of one variable?
Mainly practice with the method, cross phase multiplication, and Vader theorem, thank you

(1)6x2－13xy+6y2； (2)8x2y2+6xy－35； (3)18x2－21xy+5y2； (4)2(a+b) 2+(a+b)(a－b)－6(a－b) 2.(1)2x2+3x+1； (2)2y2+y－6； (3)6x2－13x+6； (4)3a2－7a－6； (5)6x2－11xy+3y2； (6)4m2+8mn+3n2； (7)10x2－21...

To solve a lot of quadratic equation exercises
What kind of questions do you want to test

Here, it is very rich! (0.5 + x) + x = 9.8 △ 22 (x + X + 0.5) = 9.8 25000 + x = 6x 3200 = 450 + 5x + x x x-0.8x = 6 12x-8x = 4.8 7.5 * 2x = 15 1.2x = 81.6 x + 5.6 = 9.4 x-0.7x = 3.6 91 △ x = 1.3 x + 8.3 = 10.7 15x = 3 3x-8 = 16 7 (X-2) = 2x + 3 3x + 9 = 2718 (X-2) =

If the image of linear function y = K (X-B) is in the second, third and fourth quadrant, then
A k>0 b>0 B k>0 b

D

If the function y = a ^ x + (B-1) (a > 0, a ≠ 1) passes through two, three and four quadrants, then the value ranges of a and B are?
The answer is a > 0 and a < 1, b > 0. Let's see why

If the image passes through two three four quadrants, the intercept of the image on the y-axis must be less than 0,
That is, when x = 0, y

When k > 0, the image is in one or three quadrants, in each quadrant where the image is located, in each quadrant where the image is located,
The inverse scale function y = K / x, (K ≠ 0), when k > 0, the image is in one or three quadrants, in each quadrant of the image, in each quadrant of the image, the function value y increases with the increase of the independent variable x____ When k

To reduce; enlarge

Can the coefficient of function x be negative

Yes

If the image of a function is in the third and fourth quadrant, then the function value (). A. is all positive, B. is all negative, C. is all non negative, D. positive and negative
A. All positive numbers B. all negative numbers C. all non negative numbers D. both positive and negative are possible

B should be chosen because the graph of this function only passes through three or four quadrants, which should be a parabola, that is, a quadratic function. The Y-axis of both of them is negative, so B should be chosen

If the image of a function is in the first and second quadrants, then the value of the function ()
A. All positive numbers B. all negative numbers C. all non negative numbers D. can be positive, negative or zero

If the image of the function is in the first and second quadrants, the value of the function must be positive

If a function image is below the x-axis, the function value of the function is a. all positive numbers B. all negative numbers C. all non positive numbers D. both positive and negative
D. It can be positive, negative or zero

It has to be all negative. It's obviously B. you can see how obvious it is by looking at the x.y coordinate system