Inverse function of X + 1 of function y = 2

Inverse function of X + 1 of function y = 2

x=2^y+1
2^y=x-1
Y = log2 (x-1), x > 1

The inverse function of the function y = 0.2 negative x + 1 is?
As the title

y=0.2^(-x)+1
0.2^(-x)=y-1
-x=log0.2(y-1)
x=-log0.2(y-1)
x=lg(y-1)/lg[0.2^(-1)]
x=lg(y-1)/lg5
Therefore, the inverse function of the function is:
y=lg(x-1)/lg5

Inverse function of function y = in [x + √ (x * x + 1)]

e^y=x+√(x²+1)
e^y-x=√(x²+1)
square
e^2y-2xe^y+x²=x²+1
2xe^y=e^2y-1
x=(e^2y-1)/(2e^y)
So the inverse function
y=(e^2x-1)/(2e^x)

The inverse of the function y = 1 + in (x + 1) / 2 is

The way to find the inverse function is to invert the independent variable and the dependent variable of the original function, and then use the inverted independent variable to represent the dependent variable. You are not good at this problem. I don't know that 2 is not in the range of LN. In short, you should pay attention to both. Next time you ask questions, y = 1 + ln (1 + x) / 2x = 1 + ln (1 + y) / 2ln (1 + y) =

Find the inverse function of y = 1 + in (x + 2)!

y=1+In(x+2)
y-1=ln(x+2)
x+2=e^(y+1)
x=e^(y+1)-2;
The inverse function is y = e ^ (x + 1) - 2

The inverse function of the function y = 1 + in (x-1) (x > 1) is_____

ln(x-1)=y-1,x-1=e^(y-1).x=e^(y-1)+1.
The inverse function of y = 1 + ln (x-1) (x > 1) is y = e ^ (x-1) + 1

The inverse of the function y = one third of in (x-1) (x > 1) is

3y=ln(x-1)
x-1=e^(3y)
So the inverse function is y = 1 + e ^) 3x), X ∈ R

4. Let f (x) satisfy the relation f (x) + 2F (1 / x) = 3x to find the analytic expression of the function

f(x)+2f(1/x)=3x (1)
When x = 1 / X
The original equation becomes f (1 / x) + 2F (x) = 3 / X (2)
(1)-(2)*2 -3F(X)=3X-6/X
==>F(X)=-X+2/X

The inverse of the function y = 3x-b is
How to find the inverse of a function

XY transposition
x=3y-b
So y = (x + b) / 3

The inverse of the function y = 3x + 2 is______ ．

∵ y = 3x + 2, ∵ 3x = Y-2, and 3x ＞ 0, so y ＞ 2, ∵ x = log3 (Y-2) (Y ＞ 2), the inverse function of the function y = 3x + 2 is y = log3 (X-2) (x ＞ 2), so the answer is y = log3 (X-2) (x ＞ 2)