If we know that 5x + 3 and - 4x + 4 are opposite numbers, then what is x equal to

If we know that 5x + 3 and - 4x + 4 are opposite numbers, then what is x equal to

5X+3-4X+4=0
5X-4X=-3-4
X=-7

5x + 2 and 2-4x / 3 are opposite numbers. How much is the value of X

-(5x+2)=2-4x/3
x=-12/11

It is known that the expressions 4x-3 and 5x + 12 are opposite to each other
1.4x-3-5x-12=0
2.4x-3=5x-12
3.4x-3+5x+12=0
4.4x-3=5x+12

3,

What is the image of the | X-1 | power of the function y = 2?

The image of | X-1 | power of function y = 2 is as follows:
Take x = 1 as the axis of symmetry;
On the right side of the axis of symmetry, the image is: y = 2 to the (x - 1) power
On the left side of the axis of symmetry, the image is to the (1-x) power of y = 2

Given the functions y = K (x + 1) and y = K / x, what are their approximate positions in the same coordinate system?
Say which two quadrants the inverse proportion function passes through and which three quadrants the primary function passes through

Discussion according to the situation:
(1) When k is greater than 0, the inverse proportion function passes through quadrants 1 and 3, and the primary function passes through quadrants 1, 2 and 3
(2) K equals 0
(3) When k is less than 0, the inverse proportion function passes through 2 and 4 quadrants, and the primary function passes through 1, 2 and 4 quadrants

It is known that the functions y = K (x-1) and y = 0 / x-k (x must not be 0) about X, and their images in the same coordinate system are approximately
Just tell me which quadrant

If K is greater than 0, the straight line passes through 134 quadrants and the curve passes through 24 quadrants
If K is less than 0, the straight line passes through quadrant 124 and the curve passes through quadrant 13

It is known that the functions y = K (x + 1) and y = - KX (K ≠ 0) with respect to X. their approximate images in the same coordinate system are ()
A. B. C. D.

When k ＞ 0, the coefficient of inverse proportion function - K ＜ 0, the inverse proportion function goes through two or four quadrants, and the primary function goes through one, two, and three quadrants, which is not satisfied by the original problem; when k ＜ 0, the coefficient of inverse proportion function - K ＞ 0, so the inverse proportion function goes through one or three quadrants, and the primary function goes through two, three, and four quadrants

Determine the symmetry axis and vertex coordinates of the function y = (x + 1) (2-x) image

y=-x²+x+2
=-x²+x-1/4+1/4+2
=-(x-1/2)²+9/4
So the axis of symmetry x = 1 / 2
Vertex (1 / 2,9 / 4)

The image of function y = 3x is related to the image of function y = (13) X-2_______ symmetric

y=3x,y=13x-2
The solution is: x = 1 / 5, y = 3 / 5
So, the intersection of two lines is (1 / 5,3 / 5)
Because it is known that the slopes of two straight lines are not opposite to each other, so the slope of the straight line must exist, let K be K
That is, the straight line is Y-3 / 5 = K (x-1 / 5)
Obviously, the angle between y = 3x and Y-3 / 5 = K (x-1 / 5) should be equal to the angle between y = 13x-2 and Y-3 / 5 = K (x-1 / 5)
According to the formula of the angle between two straight lines:
|(k-3)/(1+3k)|=|(k-13)/(1+13k)|
(K-3) / (1 + 3K) = (K-13) / (1 + 13K) or (K-3) / (1 + 3K) = (13-k) / (1 + 13K)
13k²-38k-3=3k²-38k-13 13k²-38k-3=-3k²+38k+13
10k²=-10 16k²-76k-16=0
No solution 4K & # 178; - 19k-4 = 0
k1=(19-5√17)/8,k2=(19+5√17)/8
Because we know that all the lines K are positive, then the line we want to find is between them. Obviously, K is also positive,
So: k = (19 + 5 √ 17) / 8
Therefore, the linear equation is Y-3 / 5 = (19 + 5 √ 17) (x-1 / 5) / 8
PS: there should be no mistake. The estimated data is not good

Can the image with the up-down translation function y = - 3 / 4x ^ be properly lowered to get a new image (3, - 18)? If so, the translation direction and distance can not be explained

Let the equation after translation be y = - 3 / 4 * x ^ 2 + C
Substituting (3, - 18), we get: - 18 = - 3 / 4 * 9 + C, and the solution is: C = - 18 + 27 / 4 = - 45 / 4
Therefore, it only needs to move down 45 / 4 units