![](data:image/svg+xml;utf8,<svg xmlns="http://www.w3.org/2000/svg" xmlns:xlink="http://www.w3.org/1999/xlink" viewBox="0 0 72 71" width="72"></svg>)
In the triangle ABC, D and E are the points of the edges of AC and BC respectively, and EC: EB = 1 / 3. It's troublesome to find the values of BC: be, DC: AC and ad: AC
BC: be = 4:1, but the latter two are calculated by another condition!
In the triangle ABC, D and E are the points on AC and BC respectively, and EC: EB = 1 / 3. To find the values of (1) BC: be, DC: AC and ad: AC, please write the process
BC:BE=（BE+EC)/BE=1+1/3=4/3
DC:AC+AD:AC=1
It can be calculated by adding conditions
As shown in the figure, in the triangle ABC, AB equals AC, D and E are the points on acab, ad equals de equals EB, BD equals BC, and the degree of angle a is calculated
It is known that in △ ABC, ab = AC, D and E are points on AC and ab respectively, and BD = BC, be = ed = ad. if angle a = a, then angle ACB = 90 degrees - A / 2. If two base angles of isosceles triangle are equal, angle a = angle AED = a, angle ade = 180 degrees - 2A, angle EDB = angle EBD = A / 2, so angle BDC = 180 degrees - angle ade - angle EDB = 3A / 2 and angle BD
Known: as shown in the figure, in △ ABC, ab = AC, BC = BD, ad = de = EB, then the degree of ∠ A is ()
A. 30°B. 36°C. 45°D. 50°
In the case of EBD (EBD = x °, and the "be = De,, \\\\\\\\\\\\\ \\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\1
RELATED INFORMATIONS
- 1. In the triangle ABC, ab = AC, angle a = 120 degrees, D is the midpoint of BC, De is perpendicular to AB and E, and the ratio of AE to EB is calculated
- 2. As shown in the figure, be and CF are the heights of △ ABC, M is the midpoint of BC, BC = 10, EF = 5, root 2, and find the area of triangle EFM kuaidiann
- 3. As shown in the figure, at the isosceles right angle △ ABC, ∠ C = 90 °, AC = BC, D is any point on AB, AE ⊥ CD is at e, BF ⊥ CD intersects the extension line of CD at F, CH ⊥ AB is at h, Give AE to g, verify: CE = BF
- 4. As shown in the figure, the elevation angle of C is ∠ CAD = 30 ° from a, the elevation angle of C is ∠ CBD = 45 ° from B, and the angle of view is ∠ ACB when measuring a and B from C=______ Degree
- 5. As shown in the figure, the elevation angle of C is ∠ CAD = 30 ° from a, the elevation angle of C is ∠ CBD = 45 ° from B, and the angle of view is ∠ ACB when measuring a and B from C=______ Degree
- 6. As shown in the figure, the elevation angle of C is ∠ CAD = 30 ° from a, the elevation angle of C is ∠ CBD = 45 ° from B, and the angle of view is ∠ ACB when measuring a and B from C=______ Degree
- 7. Known: as shown in the figure, RT △ ABC ≌ RT △ ade, ∠ ABC = ∠ ade = 90 °, try to connect two line segments by taking the points marked with letters in the figure as the end points. If the two line segments you connect satisfy one of the equal, vertical or parallel relationships, please write it out and prove it
- 8. It is known that in RT △ ABC, ∠ C = 90 ° CoSb = 23, then the value of SINB is () A. 253B. 53C. 255D. 55
- 9. As shown in the figure, in △ ABC, the points D and E are on the side of BC, and ∠ B = ∠ bad, ∠ C = ∠ CAE, BC = 8cm is known, find the perimeter, line and speed of ADE
- 10. Make parallel lines of AB, BC and AC respectively through a point P in the triangle ABC Drawing
- 11. It is known that BD is the middle line of the triangle ABC, and the perimeter of the triangle abd is 2cm longer than that of the triangle BCD. If the perimeter of the triangle ABC is 18cm and AC = 40cm, the lengths of AB and BC are obtained
- 12. In △ ABC, ab = BC, AB is the height of BC side, AE is the bisector of ∠ BAC, ead = 48 ° to find ∠ ACD
- 13. As shown in the figure, in the parallelogram ABCD, the bisector of ∠ ABC intersects CD at point E, and the bisector of ∠ ADC intersects AB at point F. try to judge whether AF and CE are equal, and explain the reason
- 14. 1993 + ABC = 2dde abcd-cdc = ABC what numbers do a, B, C and e represent? ABCD represents a number, but not the same number
- 15. What is the surface area of a regular pyramid whose vertices are on the same sphere, whose height is 3 and volume is 6
- 16. Given the cube abcd-a1b1c1d1 with side length a, O is the center of the bottom a1b1c1d1, e is a point on the edge A1B1, and the length of AE + EO is the smallest, then the minimum value is Why do I think it's a got it.. I always calculate a1e + E0 depressed
- 17. If you take any point P in the cube abcd-a1b1c1d1 with edge length a, then the probability that the distance between P and point a is not greater than a is: I know everything else, but why is it 1 / 8 of the volume of a sphere centered on a, I think it is 1 / 4!
- 18. In the cube abcd-a1b1c1d1 with edge length a, randomly take the point m in the cube. (1) find the probability that the distance between M and surface ABCD is greater than a / 3 (2) Find the probability that the distance between M and face ABCD and face a1b1c1d1 is greater than a / 3
- 19. In the triangular pyramid p-abc, PA ⊥ plane ABC, ab ⊥ AC, D, e and F are the midpoint of PA, Pb and PC respectively, connecting De, DF and ef (1) To prove the parallel plane ABC of plane def (2) If PA = BC = 2, the cosine value of dihedral angle a-ef-d is obtained when the volume of triangular pyramid p-abc reaches the maximum
- 20. As shown in the figure, in the triangular pyramid p-abc, plane ABC is perpendicular to plane APC, ab = BC = AP = PA = radical 2, angle ABC = angle APC = 90 degrees Q: how to find the area of triangle PBC?