Given the cube abcd-a1b1c1d1 with side length a, O is the center of the bottom a1b1c1d1, e is a point on the edge A1B1, and the length of AE + EO is the smallest, then the minimum value is Why do I think it's a got it.. I always calculate a1e + E0 depressed

Given the cube abcd-a1b1c1d1 with side length a, O is the center of the bottom a1b1c1d1, e is a point on the edge A1B1, and the length of AE + EO is the smallest, then the minimum value is Why do I think it's a got it.. I always calculate a1e + E0 depressed


The original cube is expanded into a plane figure, using the most segment of the line between two points. The figure is too difficult to draw, and the result is that the root sign 10A divides by 2
(see clearly, it's the midpoint of A1B1, not AB)



If we know that the height and volume of a regular pyramid whose vertices are on the same sphere are 3 and 6, then the surface area of the sphere is 0


If the radius of the sphere is 2 and the surface area of the sphere is 16 π, make a regular pyramid figure p-abcd passing through P point, make a vertical line perpendicular to the surface ABCD, and intersect with the surface ABCD at 0 point, then Po is the height of the regular pyramid. According to the volume formula of the pyramid, v = 1 / 3 × bottom area × height, the side length of the bottom surface is: root 6 connecting OB and OC, it is easy to know that △ BOC is an isosceles right triangle