In tetrahedral a-bcd with equal edge length, e and F are the midpoint of AD and BC respectively. The cosine value of the angle formed by the straight lines AF and Ce on the different planes is obtained

In tetrahedral a-bcd with equal edge length, e and F are the midpoint of AD and BC respectively. The cosine value of the angle formed by the straight lines AF and Ce on the different planes is obtained

Connect FD, do the midpoint Q of FD, and then connect EQ CQ. Because ABCD is a tetrahedron with equal edge length, AE = ed, FQ = QD, so AF / / EQ AF is twice EQ, so the angle formed by AF and EC is the angle halo formed by QE and EC. I can't tell you so much. Let's study hard

In tetrahedral a-bcd with equal edge length, e and F are the midpoint of edge AD and BC respectively, connecting AF and CE, and finding the angle of different plane lines AF and CE

If f is the midpoint of BC and G is the midpoint of be, then FG is the median line of BCE, so FG is parallel to CE

What is the inverse function of y = (ex-e-x)
Help me figure it out

This function is actually a hyperbolic sine function, and its inverse function is a hyperbolic anti sine function

The function y = e-x-ex satisfies ()
A. Odd function is a decreasing function B. even function on (0, + ∞), a decreasing function C. odd function on (0, + ∞), an increasing function D. even function on (0, + ∞), and an increasing function on (0, + ∞)

For the function y = e-x-ex, the domain of definition is r symmetric about the origin, and f (- x) = ex-e-x = - f (x), so the function y = e-x-ex is odd ∵ y = e-x-ex, ∵ y ′ = - EX-EX = - 2ex. When x > 0, y ′ < 0, ∵ the original function is a decreasing function on (0, + ∞), so a

The inverse of the function y = (e ^ x-e ^ - x) / 2 is?

Inverse function of y = 1 / x ^ 2 (x > 0)

x> 0, Y > 0
The inverse solution is x = 1 / √ y
So the inverse function is y = 1 / √ x, (x > 0)

Given the function f (x) = (lgx + 1) / (lgx-1) (x > 0, X ≠ 10), then the expression of the inverse function of F (1 / x) is

F (x) = (lgx + 1) / (lgx-1) (x > 0, X ≠ 10), then f (1 / x) = (LG1 / x + 1) / (LG1 / x-1) = (lgx-1) / (lgx + 1) let y = (lgx-1) / (lgx + 1), the solution is: lgx = (y + 1) / (1-y), x = 10 ^ (y + 1) / (1-y), understand the formula, brackets (y + 1) / (1-y), are exponents. Rewrite X and y to get: y = 10 ^ (x + 1) / (1 -

What is a condition that the function y = x-4x + 5 has an inverse function

The necessary and sufficient condition for the existence of inverse function is that the domain of definition and the domain of value of function are one-to-one mapping

The inverse function of the function y = x ^ 2-4x + 1, X ∈ [2, positive infinity] is

A:
x>=2,y=x^2-4x+1=(x-2)^2-3
So: (X-2) ^ 2 = y + 3
Because: X-2 > = 0
The square root of both sides is as follows:
x-2=√(y+3)
x=√(y+3)+2
So: the inverse function is y = √ (x + 3) + 2, x > = - 3

The inverse function of the function y = - x ^ 2 + 4x (x ≤ 2) is

We can get y = - (X-2) ＾ 2 + 4
That is, (X-2) ＾ 2 = 4-y
That is, x = (4-y) ＾ (1 / 2) + 2
The inverse function of the original function is y = (4-x) ＾ (1 / 2) + 2
From the domain of the original function, we can see that its value domain is (Y ＜ = 4), that is, the domain of its inverse function is (x ＜ = 4)
The inverse function is y = (4-x) ＾ (1 / 2) + 2 (x ＜ = 4)