(1) As shown in Figure 1, fold the △ ABC paper along de so that point a falls at the position of point a 'inside the quadrilateral bced, and try to explain that 2 ∠ a = ∠ 1 + ∠ 2; (2) as shown in Figure 2, if the △ ABC paper is folded along de so that point a falls at the position of point a' outside the quadrilateral bced, then the equivalent relationship between ∠ A and ∠ 1, ∠ 2 is______ (no need to explain the reason); (3) as shown in Figure 3, if the quadrilateral ABCD is folded along EF, so that points a and d fall on the positions of internal points a ′, D ′ of quadrilateral BCFE, please explore the quantitative relationship between ∠ a, D, 1 and 2 at this time, write down the conclusion you found and explain the reason

(1) As shown in Figure 1, fold the △ ABC paper along de so that point a falls at the position of point a 'inside the quadrilateral bced, and try to explain that 2 ∠ a = ∠ 1 + ∠ 2; (2) as shown in Figure 2, if the △ ABC paper is folded along de so that point a falls at the position of point a' outside the quadrilateral bced, then the equivalent relationship between ∠ A and ∠ 1, ∠ 2 is______ (no need to explain the reason); (3) as shown in Figure 3, if the quadrilateral ABCD is folded along EF, so that points a and d fall on the positions of internal points a ′, D ′ of quadrilateral BCFE, please explore the quantitative relationship between ∠ a, D, 1 and 2 at this time, write down the conclusion you found and explain the reason


(1) As shown in the figure, according to the nature of the fold, ∠ 3 = 12 (180 - 1), ∠ 4 = 12 (180 - 2), ∵ a + 3 + 4 = 180 ° and ∵ a + 12 (180 - 1) + 12 (180 - 2) = 180 °, we can get 2 ∠ a = 1 + 2; (2) according to the nature of the fold, ∠ 3 = 12 (180 - 1), ∠ 4 = 12 (180



The triangle ABC is folded along De, and the point a falls inside the quadrilateral bced, ∠ 1 + ∠ 2 = 100 ° to find ∠ a


∠1=180-2∠def
∠2=180-2∠edf
∠def+∠edf=180-∠f
∴∠1+∠2=360-2(∠def+∠edf)=360-2(180-∠f)=2∠f=2∠a



As shown in the figure, fold a triangular piece of paper ABC along De, and point a falls on the inside of the quadrilateral bced. If ∠ a = 30 degrees, find ∠ 1 + 2


2∠ADE+∠1=180°…… ① 2∠AED+∠2=180°…… ② ∠ADE+∠AED+∠A=180°…… ③ Please click the "adopt the answer" button below to send us a little red flower for encouragement!