![](data:image/svg+xml;utf8,<svg xmlns="http://www.w3.org/2000/svg" xmlns:xlink="http://www.w3.org/1999/xlink" viewBox="0 0 72 71" width="72"></svg>)
The perimeter of triangle ABC is 363cm, where AB = 75, BC = 1 / 3, 27
The perimeter of triangle ABC is 363cm, which is 11 √ 3
AB = root 75, which is 5 √ 3
BC = 1 / 3 radical 27, that is √ 3
So AC = 11 √ 3-5 √ 3 - √ 3
=5√3
The degree of two acute angles in isosceles triangle (non right triangle) is 1:2, so what is the maximum acute angle?
This is a common sense problem, there are only two cases of 1:2, one is right angle isosceles, the other is 72 degrees, 72 degrees, 36 degrees. If you want to set any angle in the process, you can use the proportional equation
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