Right triangle, right side is 4cm, 3cm respectively, with a right side as the axis rotation, get a cone, what is the maximum volume?

Right triangle, right side is 4cm, 3cm respectively, with a right side as the axis rotation, get a cone, what is the maximum volume?


(1) The results show that a cone with a bottom radius of 3cm and a height of 4cm is obtained by rotating the 4cm right angle side as the axis; the volume is 13 × 3.14 × 32 × 4, = 13 × 3.14 × 9 × 4, = 37.68 (cubic centimeter); (2) a cone with a bottom radius of 4cm and a height of 3cm is obtained by rotating the 3cm right angle side as the axis; the volume is 13 × 3.14 × 42 × 3, = 3.14 × 16, = 50.24 (cubic centimeter) The maximum volume is 50.24 cubic centimeter



How many cubic decimeters is the volume of a cone formed by a right triangle with a base length of 2 decimeters and a rotation of 1 circle on the axis of the line where its height lies?


The square of Wu x 2 is one third of X 3x



There are two cones with equal bottom area. One is 4 decimeters high and 48 cubic decimeters in volume. The other is 3 decimeters high. What is the volume


First of all, it is necessary to make clear the formula for calculating the volume of a cone, the bottom area x H / 3
So according to the height of a cone is 4 decimeters and the volume is 48 cubic decimeters, the area of its bottom is 48x3 / 4 = 36
So the other volume is 36x3 / 3 = 36 cubic decimeters