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When the angle BAC is equal to 50, the angle BOC is equal to 50
one hundred
Point O is the outer center of △ ABC. If ∠ BOC = 120 °, then ∠ a=____
emergency
I remember that there is a formula for this kind of problem,
The figure is about a triangle in a circle and another triangle in it. But the two sides of the second triangle bisect the two base angles of the first triangle. The vertex of the second triangle is the center of the circle
O is the outer center of △ ABC
That is, O is the center of the circumscribed circle of △ ABC
For the same arc, the center angle is equal to twice the circumference angle (angle a)
So angle a = 60 degrees
RELATED INFORMATIONS
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