As shown in the figure, the bisectors of ∠ CBD and ∠ BCE at the two outer angles of △ ABC intersect at point O, ∠ a = 40 ° to calculate the degree of ∠ BOC

The bisdividing line of "CBD" and "BCE" intersects at point O, the bisdividing line of "CBD" and "BCE" intersects at point O, and the \\\ 90 ° - 12 × 40 ° = 90 °- 20°=70°．

In triangle ABC, ab = 4cm, BC = 6, find the ratio of height AD and CE of triangle ABC

AD*BC=AB*CE,6AD=4CE,AD/CE=4/6=2/3

In triangle ABC, ad is perpendicular to h, CE is perpendicular to AB, ab = 6cm, BC = 4cm, ad = 5cm, then what is the length of CE

The area of △ ABC can be expressed as BC and ab respectively
that
AB·CE/2=BC·AD/2
6·CE=4×5
CE=10/3cm

In triangle ABC, AB is 2 cm long. BC is 4 cm long. What is the ratio of ad to CE

1:2

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