There are a (0,2), B (4,0), C (0,0), D (3,2) in the plane rectangular coordinate system. The equation for finding the circumscribed circle m of triangle ABC

There are a (0,2), B (4,0), C (0,0), D (3,2) in the plane rectangular coordinate system. The equation for finding the circumscribed circle m of triangle ABC

The center of the circle is on the vertical line of BC, that is, on the straight line x = 2,
The center of the circle is on the vertical line of AC, that is, on the straight line y = 1,
So the center of the circle m (2,1)
Radius r, R & # 178; = 2 & # 178; + 1 = 5
So the equation of triangle ABC circumcircle is (X-2) &# 178; + (Y-1) &# 178; = 5

In the plane rectangular coordinate system, a (0,4) B (0,2) C (9,1), the circle O 'is the circumscribed circle of the triangle ABC, and the coordinate of the center o' is obtained

Using the intersection point of the two sides of the vertical
The perpendicular of AB is y = 3
The midpoint of BC is (4.5,1.5), BC slope is - 1 / 9, in which the slope of vertical line is 9, and the slope of point is oblique
y-1.5=9(x-4.5)
The intersection point is (14 / 3,3), which is the center coordinate