C24 (2 is superscript, 4 is subscript) for formula and answer (urgent)

C24 (2 is superscript, 4 is subscript) for formula and answer (urgent)

C（4,2）=4×3/（2×1）=6
The method of C (m, n) is that the numerator multiplies from m and decreases the factor by 1 every time. There are n factors in total; the denominator starts from N and decreases the factor by 1 every time until 1
So C (m, n) = m (m-1) (m-2).. (m-n + 1) / N!

C (subscript 0, superscript 10) C (subscript 1, superscript 10) how to calculate C (subscript 3, superscript 5) how to calculate C (subscript 4, superscript 5) how to calculate concrete, simple and clear

Is the so-called "superscript" and "subscript" reversed?
10c0 = 1 [(how positive integer) C0 = 1];
10C1=10/1=10 ；
5C3=(5*4*3)/(1*2*3)=10
5C4=5C1=(5*4*3*2)/(1*2*3*4)=5/1=5

To prove the general addition formula in probability theory, the formula is on the graph, and the good answer is to add points
Can hi teach me

First of all, it is easy to see that P (A1 ∪ A2) = P (A1) + P (A2) - P (A1A2) satisfies the formula to be proved. When n = k, P (A1 ∪ A2 ∪. ∪ AK ∪ AK + 1) = P (A1 ∪ A2 ∪. ∪ AK) + P (AK + 1) - P (A1 ∪ A2 ∪

The figure shows the speed time picture of a student's body when doing pull-up. The weight of the student's body (except the arm) is 60kg. At 0.25s, how much strength does the student's arm give to the body? (g = 9.8m/s2)

According to the image, a = △ V △ t = 0.1 − 00.25 = 0.4m/s2. According to Newton's second law, f-mg = ma, and the solution is f = 612n. A: the strength of the student's arm to the body is 612n

200 oral arithmetic questions and answers in Grade 5 of primary school
Very urgent, please, I want 200 primary school grade 5 questions with answers! Please!

How to see acceleration direction and velocity direction in velocity time diagram

Acceleration direction: slope greater than 0, a greater than 0;: slope less than 0, a less than 0
Velocity direction: positive above T-axis, negative below T-axis,

There are answers to 200 oral arithmetic questions in grade 3. Urgent!
The simpler the better

Find out about the speed and time diagram, acceleration and time diagram

Look for it

200 mental arithmetic questions
We have to answer it tonight. We'll start school tomorrow. It's urgent tonight. We need to bring answers. It's better

6÷ 3/8 – 3/8 ÷6
=1/6x(3/8-3/8)
=1/6x0
=0
2.4/7 × 5/9 + 3/7 × 5/9
=(4/7+3/7)x5/9
=1x5/9
=5/9
3.5/2 -（ 3/2 + 4/5 ）
=5/2-3/2-4/5
=1-4/5
=1/5
4.6 ×（ 1/2 + 2/3 ）
=6x1/2+6x2/3
=3+4
=7
5.8 × 4/5 + 8 × 11/5
=8x(4/5+11/5)
=8x3
=24
6.31 × 5/6 – 5/6
=(31-1)x5/6
=30x5/6
=25
7.4/5 × 25/16 + 2/3 × 3/4
=5/4+1/2
=5/4+2/4
=7/4
8.101 × 1/5 – 1/5 × 21
=(101-21)x1/5
=80x1/5
=16
1.3/7 × 49/9 - 4/3
2.8/9 × 15/36 + 1/27
3.12× 5/6 – 2/9 ×3
4.8× 5/4 + 1/4
5.6÷ 3/8 – 3/8 ÷6
6.4/7 × 5/9 + 3/7 × 5/9
7.5/2 -（ 3/2 + 4/5 ）
8.7/8 + （ 1/8 + 1/9 ）
9.9 × 5/6 + 5/6
10.3/4 × 8/9 - 1/3
11.7 × 5/49 + 3/14
12.6 ×（ 1/2 + 2/3 ）
13.8 × 4/5 + 8 × 11/5
14.31 × 5/6 – 5/6
15.9/7 - （ 2/7 – 10/21 ）
16.5/9 × 18 – 14 × 2/7
17.4/5 × 25/16 + 2/3 × 3/4
18.14 × 8/7 – 5/6 × 12/15
19.17/32 – 3/4 × 9/24
20.3 × 2/9 + 1/3
21.5/7 × 3/25 + 3/7
22.3/14 ×× 2/3 + 1/6
23.1/5 × 2/3 + 5/6
24.9/22 + 1/11 ÷ 1/2
25.5/3 × 11/5 + 4/3
26.45 × 2/3 + 1/3 × 15
27.7/19 + 12/19 × 5/6
28.1/4 + 3/4 ÷ 2/3
29.8/7 × 21/16 + 1/2
30.101 × 1/5 – 1/5 × 21
31.58+42=
(2)87－45=
(3)125×8=

Why does the clock of movement slow down
According to the theory of relativity, the clock on the high-speed moving object will slow down, which is not the problem of the clock, but the characteristic of time itself. So is the slowing down of time relative to the observer outside the moving object, or for the high-speed moving object? Why does it slow down? Why does it almost stop when the object moves close to the speed of light?

I think this is a fallacy. I will prove it to you in N years!
The observer judges time by light, but the object moving against the speed of light will not be observed and received