It is easy to give an example that the event with probability 0 is not an impossible event, and the event with probability 1 is not an inevitable event It's better to be more detailed

One is explained above
(1) In the continuous density function, the probability of any point is 0, but the event can occur;
(2) Similarly, in the continuous density function, the probability of the whole area coverage is 1, but the event does not necessarily occur;
Here's a website for papers. You can have a look

Please write a random event with probability less than 12:______ ．

According to the meaning of the question: the probability of less than 12 random events, such as: roll a die, the number of points on the upper side is 2; so the answer is: roll a die, the number of points on the upper side is 2

Probability of relatively independent events
1. When two independent events a and B occur, is the probability of event a multiplied by the probability of event B?
If the above question holds, I would like to introduce the following two examples
(1) Two shooters shoot at the same target independently. Suppose that the probability of a shooting at the target is 0.9 and that of B shooting at the target is 0.8, then calculate the probability of the target being hit
Let a denote that a hits the target, B denote that B hits the target, and C denote that the target is hit, then C = AUB
P(C)=P(AUB)=P(A)+p(B)+P(A)P(B)…… =0.98
(2) There are 5 white balls and 3 black balls in the bag. You can take one ball from the bag twice in a row and find out the probability of taking out the white ball twice
Let a be the first time to get a white ball, and B be the second time to get a white ball
P(AB)=P(A)p(B)=25/64
I can fully understand the solutions of the above two examples, but if the formula for the first question holds, why is the probability p of the first small case in the second question not p (a) P (b), but p (AUB)?
Correct the solution in (1): P (c) = P (AUB) = P (a) + P (b) + P (a) P (b) =0.98
It should be p (c) = P (AUB) = P (a) + P (b) - P (a) P (b) =0.98

First of all, your formula is wrong. P (a ∪ b) = P (a) + P (b) - P (a) P (b)
Secondly, when the target is hit, it doesn't need a and B to happen at the same time, just need a or B to happen, and P (a) P (b) means that a and B hit at the same time. But if a hit, B didn't hit, the target also hit

A few simple questions on the application of power
If AB is opposite to each other and N is a positive integer, then it must be true
A a to the nth power and B to the nth power are opposite numbers
B A is to the power of 2n, and B is to the power of 2n
C A to the second power is equal to B to the second power
D A to the power of 2n plus one is equal to B to the power of 2n plus one
You can correctly distinguish between (- 3) to the power of 2, - 3 to the power of 2 and - (- 3)
The absolute value of X + 3 plus Y-2 to the second power is equal to 0, and X to the Y power

Choose C
Because the even power of two opposite numbers is equal
(if your B is written to the 2nth power of (- b), it's right. If it's to the 2nth power of - B, it's wrong.)

The acceleration expression of linear motion with uniform speed change is studied

a=(v2-v1)/t
a=(v2^2-v1^2)/2S
a=(2S-2v1t)/t^2

A mathematical problem about power calculation in grade one of junior high school, please help me!
^Is the power - is the minus sign + is the plus sign
2-2^2-2^3-2^4-2^5-2^6-2^7-2^8-2^9+2^10
Hope that the answer can also indicate the symbol, thank you! The best process more detailed!
I hope it can be simplified

First calculate: - 2 ^ 9 + 2 ^ 10
Obviously - 2 ^ 9 + 2 ^ 10 = - 2 ^ 9 + 2 * 2 ^ 9 = 2 ^ 9,
The formula becomes: 2-2 ^ 2-2 ^ 3-2 ^ 4-2 ^ 5-2 ^ 6-2 ^ 7-2 ^ 8 + 2 ^ 9, and then it is calculated as: - 2 ^ 8 + 2 ^ 9
As above, it can be calculated that: - 2 ^ 8 + 2 ^ 9 = 2 ^ 8,
.
Finally, it is simplified as: 2-2 ^ 2 + 2 ^ 3 = 2 + 2 ^ 2 = 2 + 4 = 6
After answering, I don't know if the questioner is clear

The formula of acceleration in the relationship between displacement and time of uniform velocity linear motion

S=Vot+1/2at²；
Vt=V0+at；
Vt²-V0²=2aS

A math problem about power
(- 2) to the power of 2008 * (half) to the power of 2007

Original formula = (- 2) ^ 2008 * (2 ^ - 1) ^ 2007
=2^2008 * 2^(-2007)
=2^(2008-2007)
=2^1
=2
The even power of a negative number is equal to the even power of the positive number

The derivation formula for the velocity of the midpoint position of the uniform variable speed linear motion?

Let v be the velocity at the midpoint of the displacement
Let the total displacement be 2x
Vt^2-Vo^2=2a(2x)=4ax
V^2-Vo^2=2ax
Comparison of the two formulas
V1 = root [(VT ^ 2 + VO ^ 2) / 2]

Please write a mixed operation problem of rational number and solve it
1 must contain five operations: addition, subtraction, multiplication, division and power
Divisor 2 must be a fraction
The base of a 3-Power operation must be a negative fraction
4. The calculation result is equal to 2012

(-1/2)^2/(1/4)*1-1+2012
=1/4/(1/4)*1-1+2012
=1*1-1+2012
=1-1+2012
=2012

It is easy to give an example that the event with probability 0 is not an impossible event, and the event with probability 1 is not an inevitable event It's better to be more detailed