Let the integer part of √ 17-2 be x and the decimal part be y, and find the value of X + y + 2 / y PS: 17 is inside the root, and - 2 is outside the root

Let the integer part of √ 17-2 be x and the decimal part be y, and find the value of X + y + 2 / y PS: 17 is inside the root, and - 2 is outside the root

x=2,y=√17-4,x+y=√17x+y+2/y=√17+2/(√17-2)=√17+2(√17+2)/[(√17-2)(√17+2)]=√17+2(√17+2)/13=(28√17+4)/13(x+y+2)/y=(√17+2)(√17+2)/[(√17-2)(√17+2)]=(17+2√17+4)/(17-4)=(21+2√17)/13...

Let the integer part of √ (11-6 √ 2) be x and the decimal part be y, then what is the value of X + y + 1 / y?
An answer will do

4-1 / 2 times root 2
The method is to write 11-6 √ 2 as the square of 3 - √ 2, then it will be simple, x = 1, y = 2 - √ 2

When solving the equation 0.2x + 1 = 0.2x-0.1 of 0.2, you can first convert the decimal in the denominator into an integer, and get (),
Then go to the denominator, that is, multiply () on both sides of the equation to get the equation
When solving the equation 0.2x + 1 = 0.2x-0.1 of 0.2, you can first convert the decimal in the denominator into an integer, and get（

Then go to the denominator, that is, multiply (10) on both sides of the equation to get the equation
4x+10=5x-1
x=11
When solving the equation 0.5 of 0.2x + 1 = 0.2 of 0.1 x-0.1, you can first convert the decimal in the denominator into an integer, and get the result
2/5x+1=1/2x-1/10

Solve the equation X-1 of 2 = 2x + 1 of 3-4 to remove the denominator

2 (x-1) = 12 - (2x + 1)
Remove the bracket, get: 2x-2 = 12-2x-1
By shifting items and merging similar items, we get 4x = 13,
When the coefficient is changed to 1, x = 13 / 4

Solve the equation 2-3 of 2X-4 = - 6 of X-7, get ()
A.2-2（2x-4)=-(x-7) b.12-2(2x-4)=-x-7 C.12-2（2x-4)=-(x-7) D12-(2x-4)=-(x-7)

C.12-2（2x-4)=-(x-7)

To solve the equation 0.5 / 0.2x + 1 = 0.2 / 0.1x-0.1 + 1, you can first convert the decimal in the denominator into an integer, and then get the denominator, that is, multiply the two sides of the equation

0.5/0.2x+1=0.2/0.1x-0.1+1
5/2x=2x-0.1
1/2x=-0.1
x=-0.2

If real numbers a and B satisfy A3 + B3 + 3AB = 1, then a + B=______ ．

According to the meaning of the title: (a + b) (A2 + b2-ab) + 3AB = 1 (a + b) [(a + b) 2-3ab] + 3AB = 1 (a + b) (a + b) 2-3ab (a + b) + 3ab-1 = 0 [(a + B) 3-1] - 3AB (a + B-1) = 0 (a + B-1) [(a + b) 2 + 1 + A + b] - 3AB (a + B-1) = 0 (a + B-1) [(a + b) 2 + 1 + A + b-3ab] = 0 (a +

If real numbers a and B satisfy A3 + B3 + 3AB = 1, then a + B=______ ．

According to the meaning of the title: (a + b) (A2 + b2-ab) + 3AB = 1 (a + b) [(a + b) 2-3ab] + 3AB = 1 (a + b) (a + b) 2-3ab (a + b) + 3ab-1 = 0 [(a + B) 3-1] - 3AB (a + B-1) = 0 (a + B-1) [(a + b) 2 + 1 + A + b] - 3AB (a + B-1) = 0 (a + B-1) [(a + b) 2 + 1 + A + b-3ab] = 0 (a +

If real numbers a and B satisfy A3 + B3 + 3AB = 1, then a + B=______ ．

According to the meaning of the title: (a + b) (A2 + b2-ab) + 3AB = 1 (a + b) [(a + b) 2-3ab] + 3AB = 1 (a + b) (a + b) 2-3ab (a + b) + 3ab-1 = 0 [(a + B) 3-1] - 3AB (a + B-1) = 0 (a + B-1) [(a + b) 2 + 1 + A + b] - 3AB (a + B-1) = 0 (a + B-1) [(a + b) 2 + 1 + A + b-3ab] = 0 (a +

If real numbers a and B satisfy a * a * a + b * b * B + 3AB = 1, find the value of a + B

A * a * a + b * B + 3AB = 1 (a + b) ^ 3-3ab (a + b) + 3AB = 1 (a + b) ^ 3-1 - [3AB (a + b) - 3AB] = 0 (a + B-1) [(a + b) ^ 2 + (a + b) + 1] - 3AB (a + B-1) = 0 (a + B-1) [(a + b) ^ 2 + (a + b) + 1-3ab] = 0, that is, a + B-1 = 0 or (a + b) ^ 2 + (a + b) + 1-3ab = 0