1. Given sin α = (2 √ 5) / 5, find Tan (α + π) + [sin (5 / 2 π + α) / cos (5 / 2 π - α)] 1. Given sin α = (2 √ 5) / 5, find Tan (α + π) + [sin (5 / 2 π + α) / cos (5 / 2 π - α)] 2. (1) if angle α is the second quadrant angle, simplify Tan √ [(1 / sin ^ a) - 1] (2) Simplification: [√ (1-2sin130 ° cos130 °)] / [sin130 ° + √ 1-sin ^ 2 (130 °)]

1. Given sin α = (2 √ 5) / 5, find Tan (α + π) + [sin (5 / 2 π + α) / cos (5 / 2 π - α)] 1. Given sin α = (2 √ 5) / 5, find Tan (α + π) + [sin (5 / 2 π + α) / cos (5 / 2 π - α)] 2. (1) if angle α is the second quadrant angle, simplify Tan √ [(1 / sin ^ a) - 1] (2) Simplification: [√ (1-2sin130 ° cos130 °)] / [sin130 ° + √ 1-sin ^ 2 (130 °)]

1. sinα=(2√5)/5 cossα=±(3√5)/5
tan(α+π)+[sin(5/2π+α)/cos(5/2π-α)]=tanα+[sin(1/2π+α)/cos(1/2π-α)]
=tanα+[sin(1/2π-α)/cos(1/2π-α)]=tanα+(cosα)/(sinα)=tanα+cotα
=1/(sinαcosα)=±5/6
two
(1)tanα√[(1/sin^2a)-1]=tanα√[(1-sin^2a)/sin^2a]=tanα|cotα|
The ∵ angle α is the second quadrant angle ∵ cot α