Let LG2 = A and Lg3 = b be known It is known that LG2 = A and Lg3 = B. let a and B denote the following logarithm （1）lg5 (2) Log (2) 3 (3) Log (12) 25

Let LG2 = A and Lg3 = b be known It is known that LG2 = A and Lg3 = B. let a and B denote the following logarithm （1）lg5 (2) Log (2) 3 (3) Log (12) 25

lg5=lg10/2=lg10-lg2=1-a
log（2）3=lg3/lg2=b/a
log（12）25=lg25/lg12=2lg5/lg3+lg4=2(1-a)/b+2a

Given LG2 = a, Lg3 = B, find the value of the following formula
㏒₃4
㏒₂12
lg3/2

1,㏒₃4=lg4/lg3=2lg2/lg3=2a/b
2,㏒₂12=lg12/lg2=lg4*3/lg2=(lg4+lg3)/lg2=(2a+b)/b
3,lg3/2=lg3-lg2=b-a

Why is logarithm lg1.6 equal to 0.2

The logarithm index is: 0.2 power of 10 equals 1.6
The 0.2 power of 10 is equal to the 1 / 5 power of 10, that is, the fifth power of 10, which is an irrational number. It can't be equal to 1.6, only about 1.6
lg(1.6)=lg(16/10)=lg16-lg10=4lg2-1=4*0.3-1=0.2
LG2 = 0.3 should be known, it should be memorized

What is the logarithm lg174? How to calculate it?
What if we want to reverse the calculation?
That is to say, I know LG x = 2.24
X?

lg174=2.240...
Using a calculator