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Log 3 times the root 3 minus LG root 10 plus log 2 / 3 times the root 2, I don't know if someone can understand it. Let's give it a process
How much is the root 3 of log3?
If it is based on 3
=The third power of log3 minus the first power of LG10 plus the third power of log2
=Log 2 of 3 / 2-1 / 2 + 2 to the third power and then negative 1 / 2 power
=1 / 2 power of 1 + 3 = root 3 of 1 + 3
Given LG2 = a, Lg3 = B, find the value of LG18
Because LG18 = LG (2 * 3 * 3) = LG2 + Lg3 + Lg3
=a+b+b=a+2b
Answer a + 2B
What is LG18 / 25 equal to? LG2 = a, Lg3 = B, expressed by the formula containing a and B
Urgent! 1
lg18/25=lg18-lg25=lg(2X3^2)-2lg5
=lg2+2lg3-2lg5
=lg2+2lg3-2(lg10-lg2)
=3lg2+2lg3-2
3a+2b-2
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