If the area of the triangle formed by the function y = - 3 / 2x + B and the coordinate axis is 12, then B =?

If the area of the triangle formed by the function y = - 3 / 2x + B and the coordinate axis is 12, then B =?

Let a function y = - 3 / 2x + B intersect X-axis at point a and y-axis at point B,
∵ K=-3/2,S△OAB=½OA*OB=12,
Let | OA | = 2m, then | ob | = 3M,
∴2m*3m=24,
∴m²＝4,m＝±2,
| ob | = 6, i.e. B = ± 6

The intersection of function y = 1 / 2x ^ 2 and function y = x + 2 / 3 is a and B. point a is on the right side of point B. calculate the area of △ abo
RT urgent

Provide the following ideas
The intersection coordinate is the solution of a system of equations composed of two functions
1. Find the solution of the equations, that is, the coordinates of two points
2. Make vertical lines to the x-axis through points a and B to get trapezoid
3. Subtract the area of two right triangles from the trapezoid area
The remaining area is the area of the triangle abo
I believe you are the best

The coordinate of the intersection of the function y = 2x + 4 and the Y axis is the coordinate of the intersection of the function y and the X axis is the area of the triangle enclosed by the function y and the two axes is?

Intersecting with the Y axis is x = 0, intersecting with the X axis is y = 0
When y = 0, 2x + 4 = 0, x = - 2
When x = 0, y = 4
Therefore, the two intersections are: (0,4), (- 2,0)
Area = 1 / 2 * x * y = 0.5 * 2 * 4 = 4