When m is a value, the function y is equal to the power of 2m minus 1 of (m plus 3) x plus 4x minus 5 (x is not 0), which is a first-order function

When m is a value, the function y is equal to the power of 2m minus 1 of (m plus 3) x plus 4x minus 5 (x is not 0), which is a first-order function

When y = (M + 3) x to the power of 2m-1 + 4x-5 satisfies 2m-1 = 1 or M + 3 = 0, it is a first-order function, so when m = 1 or M = - 3, the original function is a first-order function

If the sum of the N-1 power of y to the fourth power of 3x and the 3 power of y to the 2m power of negative 4x is still a monomial, then M + N:

4=2m
m=2
n-1=3
n=4
m+n=2+4=6

Given f (x) = AX2 + BX + C. (I) when a = - 1, B = 2, C = 4, find the solution set of F (x) ≤ 1; (II) when f (1) = f (3) = 0, and when x ∈ (1,3), f (x) ≤ 1 is constant, find the minimum value of real number a

(I) when a = - 1, B = 2, C = 4, f (x) = - x2 + 2x + 4, then f (x) ≤ 1, i.e. x2-2x-3 ≥ 0, X (x-3) (x + 1) ≥ 0, the solution is x ≤ - 1, or X ≥ 3. So the solution set of inequality f (x) ≤ 1 is {x | x ≤ - 1, or X ≥ 3}; (II) because f (1) = f (3) = 0, so f (x) = a (x-1) (x-3), f (x) = a (x-1) (x-3) ≤ 1, which is constant in X ∈ (1, 3), i.e. − a When x ∈ (1,3), 0 ＜ (x − 1) (3 − x) ≤ [(x − 1) + (3 − x) 2] 2 = 1, the equal sign is obtained if and only if X-1 = 3-x, i.e. x = 2; Let g (x) = a (x-1) (x-3) - 1 = ax2-4ax + 3a-1 = a (X-2) 2-a-1& When a ＞ 0, Yi Zhi is tenable in X ∈ (1,3), which conforms to the following conditions: & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; ③ when a ＜ 0, then - A-1 ≤ 0, so - 1 ≤ a ＜ 0. & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; In conclusion, a ≥ - 1, so the minimum value of a is - 1