If the point P (2m-1,1) is on the image with inverse scale function y = 1 / x, then M =?

If the point P (2m-1,1) is on the image with inverse scale function y = 1 / x, then M =?

You can substitute the point P into the function, that is, when x = 2m-1, y = 1, 1 = 1 / (2m-1), and the solution is m = 1

Given that the point P (1, a) is on the image of the inverse scale function y = KX (K ≠ 0), where a = M2 + 2m + 3 (M is a real number), then the image of this function is on the second dimension______ Quadrant

A = M2 + 2m + 3 = M2 + 2m + 1 + 2 = (M + 1) 2 + 2, ∵ (M + 1) 2 ≥ 0 ∵ a ≥ 2, and point P (1, a) is on the image of inverse scale function y = KX (K ≠ 0), ∵ k = a > 0, and the image of ∵ function is in the first and third quadrants

It is known that point a (- 2,3) is on the image of inverse scale function, and the value of (1) analytic expression of inverse scale function (2) m is obtained through (- 2,2m + 1) of the image

Let the analytic expression of the inverse proportion function be y = K / x, then (- 2,3), 3 = K / (- 2), so k = - 2 * 3 = - 6; so the analytic expression of the inverse proportion function is y = - 6 / X; 2m + 1 = - 6 / (- 2)
2m+1=3
2m=2
m=1.

If the image of function y = m + 2x is in each quadrant, the value of function y increases with the increase of independent variable x, then the value range of M is ()
A. m＜-2B. m＜0C. m＞-2D. m＞0

In each quadrant of the image of the function y = m + 2x, the value of the function y increases with the increase of the independent variable x, M + 2 ＜ 0, the solution is m ＜ - 2, so a