1. Find the linear equation that passes through the point a (- 2,2) and the area of the triangle enclosed by two coordinate axes is 1 2. If the line 3ax-y-1 = 0 is perpendicular to the line (A-2 / 3) x + y + 1 = 0, find the value of M 3. If the line ax + y + 2 = 0 intersects with the line segment connecting a (- 2,3) and B (3,2), find the value range of A The second problem is a

1. Find the linear equation that passes through the point a (- 2,2) and the area of the triangle enclosed by two coordinate axes is 1 2. If the line 3ax-y-1 = 0 is perpendicular to the line (A-2 / 3) x + y + 1 = 0, find the value of M 3. If the line ax + y + 2 = 0 intersects with the line segment connecting a (- 2,3) and B (3,2), find the value range of A The second problem is a

1. Let the linear equation: y = KX + B
Y = KX + 2k-2
Intersection with two axes (2 / k-2,0) (0,2k-2)
So s = | (2 / K-2) (k-1) | = 1
So: k = 2 or 1 / 2
Linear equation: y = 2x + 2 or y = x / 2-1
It should be ball a
The slope of the two vertical lines is multiplied by - 1
3a*（2/3-a）=-1
The value of a is - 1 / 3 or 1
3. (I) when a = 0, the line obviously intersects the line segment;
(II) when a is not o, the slope of the straight line is - A. from the expression ax + y + 2 = 0, we know that the straight line obviously passes through the point (0, - 2) and record it as the point C (0, - 2). Obviously, the straight line rotates around the point C with the change of a, so we connect AC and BC, and find out that the slopes of AC and BC are - 5 / 2 and 4 / 3 respectively

1. If the inclination angle of the line x = 1 is alpha, fill in the blank
2. If AB is less than 0 and BC is less than 0, then the line ax + by = C passes through the () quadrant
3. The abscissa of a point P on the line X-Y + 1 = 0 is 3. If the line rotates 90 degrees counterclockwise around the point P to get a line L, then the equation of the line L is?
4. Given point a (1,0), point B moves on the straight line x + y = 0. When line AB is the shortest, the coordinates of point B are?
5. A straight line passes through point m (- 3,4), and the sum of intercept on two coordinate axes is 12. The equation of this straight line is?

1.90°
2. The linear equation can be transformed into y = - A / BX + C / b
Because Ab0
Because BC

In △ ABC, it is known that (a + B + C) (a + B-C) = 3AB, and 2cosasin B = sinc

From the sum formula of internal angles of triangles, 2cosasinb = sinc = sin (a + b) ｜ 2cosasinb = sinacosb + sinbcosa ｜ sinacosb sinbcosa = 0, ｜ sin (a-b) = 0, ｜ a = B ∵ (a + B + C) (a + B-C) = 3AB ∵ (a + B) 2-c2 = 3AB, that is, A2 + b2-c2 = AB, COSC = A2 + B2 − c22ab = 12 ∵ 0 ∵ C ∵ π, ｜ C = π 3, ｜ a = b = C = π 3, so △ ABC is an equilateral triangle