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It is known that the two zeros of the function f (x) = ax & # 178; + BX + C are - 1 and 2, and f (5)
The two zeros are - 1 and 2
So the axis of symmetry is x = (- 1 + 2) / 2 = 1 / 2
And because f (5)
The zeros of function f (x) = x ^ 2 + ax + B are - 1 and 2. How to find the approximate interval of the zeros of function g (x) = ax ^ 3 + BX + 4
Is there any other interval besides 1 to 2? For example - 1 to 2 is OK
The zeros of F (x) = x ^ 2 + ax + B are - 1 and 2
1 and 2 are the roots of the equation x ^ 2 + ax + B = 0,
According to Weida's theorem: a = - 1, B = - 2
The function g (x) = - x ^ 3-2x + 4
It is easy to know that G (1) = 1 > 0, G (2) = - 8
If the function f (x) = 4x & # 178; - MX + 5 is an increasing function in the interval [- 2, positive infinity), then the value range of F (1) is____ ?
The quadratic function, with the opening upward, is increasing on the right side of the symmetry axis, and the symmetry axis is x = m / 8,
Therefore, from the fact that the interval [- 2, positive infinity) is an increasing function, we can get that the interval [- 2, positive infinity) is on the right side of the symmetry axis X = m / 8;
M / 8 ≤ - 2, m ≤ - 16;
So: F (1) = 9-m ≥ 25
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