The set of positive integers divided by 5 and 2 is expressed as

The set of positive integers divided by 5 and 2 is expressed as

{n|n=5k+2,k∈N*}

Using description method to describe the set of positive integers divided by 5 and 3

{x | x = 5K + 3, K is an integer}
Hope to adopt

A set of integers divided by one by three a set of positive integers divided by one by three

A set of integers divided by 3 and 1
={n | nmod (3) = 1, n is an integer}
A set of 1 positive integers divided by 3
={n | nmod (3) = 1, n is a positive integer}

The set of positive integers divided by 5 to 1?
Why is the answer {x | x = 5N + 1, n ∈ n} not {x | x = 5N + 1, X ∈ n +}
Why n ∈ n instead of X ∈ n.

0 is OK, but n + doesn't include 0
X is obtained by N, so you only need to define n

How to express "the set of positive integers divided by 5 and 1"?
Can it be expressed as follows: {x ∈ n * vertical ((x-1) / 5) ∈ n}

{x│x=5y+1,y∈N}
(n stands for the set of natural numbers)

The set of positive integers divided by 5 and 3

{x|x=5k+3,k∈N }

To express "a set of positive integers divided by three and remaining one" by descriptive method:______ ．

Solution; ∵ all positive integers divided by 3 and remaining 1 can be written in the form of integral multiple of 3 plus 1, that is, x = 3K + 1, K ∈ n, the description method is used to express the set of positive integers divided by 3 and remaining 1: {x| x = 3K + 1, K ∈ n} so the answer is: {x| x = 3K + 1, K ∈ n}

The set of positive integers divided by 5 to 1
The answer is {x │ x = 5Y + 1, y ∈ n} (n stands for the set of natural numbers)
Isn't it a set of positive integers? How about ∈ n, not ∈ n *? Please be more specific,

N represents the set of natural numbers, that is, 0 and positive integers;
When y = 0, x = 1 is a positive integer
The set of positive integers is x (range), and Y ∈ n is the domain

Let a = {(x, y) | x ^ 2-y ^ 2 / 36 = 1}, B = {(x, y) | y = 3 ^ x}, and the number of subsets of a ∩ B be
There are eight

A is all the points on the hyperbola with (± √ 37,0) as the focus and the absolute value of the distance difference between the two focuses is 1
B is all the points on y = 3 ^ X
As can be seen from the drawing, hyperbola and y = 3 ^ X have three focal points, set as A1, A2 and A3
So there are eight subsets: {&;}, {A1}, {A2}, {A3}, {A1, A2}, {A1, A3}, {A2, A3}, {A1, A2, A3}

Let a = {(x, y) | x ^ 2 / 4 + y ^ 2 / 16 = 1}, B = {(x, y) | y = 3 ^ x}, then the number of subsets of a ∩ B is sense
Let a = {(x, y) | x ^ 2 / 4 + y ^ 2 / 16 = 1}, B = {(x, y) | y = 3 ^ x}, then the number of subsets of a ∩ B is
Let a = {x | x-a | 2, X ∈ r}, if a is a subset of B, then real a and B must satisfy a | a + B | ≤ 3 B | a + B | ≥ 3 C | A-B | ≤ 3 D | A-B | ≥ 3

(1) Is the number of intersections of ellipses represented by set a and functions represented by set B
(2) Solution A: A-1