For three numbers ABC, min {a, B, C} is used to represent the smallest of the three numbers, for example: Min {- 1,2,3} = - 1, If min {2, - 2,4-2x} = - 2, then the value range of X is?

For three numbers ABC, min {a, B, C} is used to represent the smallest of the three numbers, for example: Min {- 1,2,3} = - 1, If min {2, - 2,4-2x} = - 2, then the value range of X is?

If min {2, - 2,4-2x} = - 2,
Then, the smallest number of 2, - 2 and 4-2x is - 2
Thus, 4-2x ＞ - 2
∴ x＜3

For any two real numbers a and B, min (a, b) is used to represent the smaller number, then the solution of the equation x · min (x, - x) = - 2x + 1 is
A: 1, - 1 + radical 2 B: 1, - 1-radical 2 C: - 1, - 1 + radical 2 D: - 1, - 1-radical 2

There are two cases
(1) When x ≥ 0, X ≥ - x, min (x, - x) = - x, the equation x · min (x, - x) = - 2x + 1 becomes
-X & # 178; = - 2x + 1, that is, (x-1) &# 178; = 0, x = 1
(2) When x

Let a, B, C be positive real numbers, and a + B + C = 1, then 1 / A + 1 / B + 1 / C ≥ how many

Replace all 1 in the molecule with a + B + C, and then use the basic inequality a + b > = radical AB to know that when a = b = C = 1 / 3, the minimum value is 9

Inverse function of function f (x) = SiNx, X ∈ (π / 2,3 π / 2), f ^ - 1 (x)

π - x ∈ (- π / 2, π / 2), y = SiNx = sin (π - x), so π - x = arcsiny, x = π - arcsiny, so the inverse function is y = π - arcsinx