Given that the minimum positive period of the function f (x) = sin (ω x + π 3) (ω > 0) is π, then the image of the function () A. On line x = π 3 symmetry B. on point (π 3,0) symmetry C. on line x = - π 6 symmetry D. on point (π 6,0) symmetry

Given that the minimum positive period of the function f (x) = sin (ω x + π 3) (ω > 0) is π, then the image of the function () A. On line x = π 3 symmetry B. on point (π 3,0) symmetry C. on line x = - π 6 symmetry D. on point (π 6,0) symmetry

Then f (x) = sin (2x + π 3), ∵ f (x) takes the maximum value on the symmetry axis, ∵ f (π 3) = sin π ≠± 1, so a is wrong; f (- π 6) = sin 0 ≠± 1, so C is wrong; and the abscissa of the symmetry center of F (x) = sin (2x + π 3) is obtained from 2x + π 3 = k π: x = K