What is the value of a when (X-10) (x-a) + 1 is the complete square formula Factorization (valid before 20:00, April 6, 2010)

What is the value of a when (X-10) (x-a) + 1 is the complete square formula Factorization (valid before 20:00, April 6, 2010)

The reason is: 1. X & sup2; - (a + 10) x + 10A + 1,2. [x-0.5 (a + 10) & sup2;] & sup2;, 3. X & sup2; + 0.25 (a + 10) & sup2; - (a + 10) x, from 1,3 parts, we can get 0.25 (a + 10) & sup2; = 10A + 1, so, (a + 10) & sup2; = 40A + 4, reduced to a & sup2; - 20A + 96 = 0, finally we get that

If x ^ 2 + 2 (a + 4) x + 36 is a complete square formula, find the value of A

The original formula can be understood as (x + 6) ^ 2, split into x ^ 2 + 12x + 36, so 2 (a + 4) = 12, the solution is a = 2

19.9 square is calculated by the complete square formula, and (x-0.5) square - (x-1) (X-2)

19.9 square = (20-0.1) ^ 2 = 400-2 * 20 * 0.1 + 0.01 = 400-4 + 0.01 = 396.01
(x-0.5) square - (x-1) (X-2)
=x^2-x+1/4-x^2+3x-2
=2x-7/4

How to solve (5-x) (the square of 25 + 5x + x) by using the complete square formula?

（5-x）（25+5x+x^2）=（5-x）（25-10x+x^2+15x）=（5-x）【（5-x）^2+15x】
=（5-x）（5-x+15x）=（5-x）（5+14x）

Calculate with complete square formula: (x-3 / 1) (x + 3 / 1) (x ^ 2-9 / 1)

Original = (X & # 178; - 9 / 1) (X & # 178; - 9 / 1)
=X^4-9/2X²+81/1

Fill in the blanks with the complete square formula: 4-12 (X-Y) + 9 (X-Y) 2 = (??????) 2．

4-12（x-y）+9（x-y）2，=[3（x-y）-2]2，=（3x-3y-2）2．

Given that (x-1) (x + 3) (X-8) + m conforms to the complete square formula, the value of M can be obtained

(x-1)(x+3 )(x-8)=x³-4x²-29x-24
Then, M = - X & # 179; + 5x & # 178; + 31x + 25
Or M = - X & # 179; + 25X + 23.. too much

1. (x + 4) ^ 2. (2a-3 ^ 2) how to use the complete square formula to solve these two problems

1.(x+4)²=x²+8x+16
2.(2a-3)²=4a²-12a+9
Potato group Shao Wenchao answers questions for you
If you don't understand this question, you can ask,

Try to prove that the sum of the product of four continuous integers and 1 is the square of an odd number
Give the answer before 5 o'clock today,

Let the first natural number be a, then the sum of the product and 1 of these four continuous natural numbers is a * (a + 1) * (a + 2) * (a + 3) + 1 A * (a + 1) * (a + 2) * (a + 3) + 1 = a * (a + 3) * (a + 1) * (a + 2) + 1 = (a ^ 2 + 3a) (a ^ 2 + 3A + 2) + 1 = (a ^ 2 + 3a) (a ^ 2 + 3a) + 2 (a ^ 2 + 3a) + 1 = (a ^ 2 +... (a ^ 2 + 3a) +

Try to explain that the product of four consecutive integers plus one is the square of an integer

Suppose the equation