The solution of equation 4x-3y = 13 and () in the following equation is x = 1y = -3 A. 5x+6y=23B. 2x+5y=17C. 8x-y=5D. 3x+13y=2

The solution of equation 4x-3y = 13 and () in the following equation is x = 1y = -3 A. 5x+6y=23B. 2x+5y=17C. 8x-y=5D. 3x+13y=2

A. Substituting x = 1y = - 3 into equation 5x + 6y = 23, left = - 13 ≠ right, so it is not the solution of the equation, so the option is wrong; B. substituting x = 1y = - 3 into equation 2x + 5Y = 17, left = - 13 ≠ right, so it is not the solution of the equation, so the option is wrong; C. substituting x = 1y = - 3 into equation 8x-y = 5, left = - 11 ≠ right, so it is not the solution of the equation, so the option is wrong; D. substituting x = 1y = - 3 into equation 3x + 13y = 2, left= 2 = right, so it is not the solution of the equation, so the option is correct

How to solve this equation x-60-13 / 32 = 1 / 4x-5

x-60-13/32=1/4x-5
x-1/4x=60-5+13/32
3 / 4x = 55 and 13 / 32
3/4x=1773/32
x=1773/32÷3/4
x= 591/8

Solution set of equation x ^ 2 + y ^ 2-4x + 6y + 13 = 0

x²＋y²－4x＋6y＋13＝0
（x－2）²＋（y＋3）²＝0
∵（x－2）²≥0,（y＋3）²≥0
∴x－2＝0,y＋3＝0
That is, x = 2, y = - 3

(x square + 2x) square-7 (x square + 2x) - 8 how to multiply by cross,

(x²+2x)²-7(x²+2x)-8
=[(x²+2x)+1][(x²+2x)-8]
=(x²+2x+1)(x²+2x-8)
=(x+1)²(x+4)(x-2)
I understand. Please accept,
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The square of 2x - x-3.2x + 5-7. Solve by cross multiplication

Solution
2x²-x-3
=(2x-3)(x+1)
2x²+5-7
=(2x-7)(x+1)

Solve the equation x square - 10x + 24 = 0 by cross multiplication

X square - 10x + 24 = 0
(x-6)(x-4)=0
x-6=0
x=6
x-4=0
x=4

Using substitution method to solve the equations 4x − 3Y = 2 ① 2x + y = 6 ②

From 2, we get y = 6-2x 3, substitute 3 into 1, we get 4x-3 (6-2x) = 2, 4x-18 + 6x = 2, 10x = 20, x = 2. Substitute x = 2 into 3, we get y = 2. So the solution of the original equations is x = 2Y = 2

The solution of 2x + y = 5 4x + 3Y = 11 by global substitution method

4x+3y=11　
2（2x+y）+y=11
2*5+y=11
y=1
Take y = 1 into 2x + y = 5
2x+1=5
2x=4
x=2

{4x + 3Y = 5,2x-y = - 5 by substitution

4x-3y = 5 2x-y = 2 using substitution method to solve equation

By transforming 2x-y = 2 into y = 2x-2 and substituting y into 4x-3y = 5, we can get the solution of x = 2 / 1y = - 1