If the solution of the equation AX = 6 of X is a natural number, then all possible values of integer a are

If the solution of the equation AX = 6 of X is a natural number, then all possible values of integer a are

1,2,3,6

If the solution AX = 3 of the equation of X is a natural number, then the value of integer a is

Because x is a natural number, i.e. 1,2,3
If a is an integer, then,
Two solutions of a = 1 or a = 3

The equation n △ 19 = 76 needs the process of solving the equation and the test process
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N=76×19
N=1444
Test: left = 1444 △ 19 = 76
Right = 76
Left = right
N = 1444 is the solution of the original equation

Solution equation: 4x & # 178; + 45x + 45 =

x=(-45±3√145)/8

X ^ 2 + 3x = 2, find the value of 2x ^ 2 + 6x ^ 2-4x

It's 2x & # 179; + 6x & # 178; - 4x
=2x(x²+3x)-4x
=4x-4x
=0

Given 3x-6x-5 = 0, find the value of 2x-4x + 6
It's not the square of 3x

Is it 3x & sup2; - 6x-5 = 0?
3x²-6x=5
Two years by two
6x²-12x=10
Divide two sides by three
2x²-4x=10/3
So 2x & sup2; - 4x + 6 = 10 / 3 + 6 = 28 / 3

Given that the value of 2x ^ 2 + 3x + 5 is 6, what is the value of the algebraic formula 6x ^ 2 + 9x-3? - 4x ^ 2-6x-5?

2x²+3x+5=6
2x²+3x=1
6x²+9x-3
=3(2x²+3x)-3
=3×1-3
=0
-4x²-6x-5
=-2(2x²+3x)-5
=(-2)×1-5
=-7

How to find the derivative of the curve y = e ^ ax

Y = e ^ (AX) this is a composite function,
y'=[e^(ax)]'=(ax)'[e^(ax)]=a*e^(ax)

Help find a derivative y = e ^ (AX) + 3x

y=e^(ax)+3x
y'= a* e^(ax)+3

The derivative of y = e ^ ax + 3x is equal to? A ∈ R
E ^ ax + 3, right? A is a real number without compound derivative

y'=(e^ax +3x)'=(e^ax)' +(3x)'=(e^ax)*a +3=a(e^ax) +3