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F (x) = - cosx + cos (90-x), if x is in the range of 0 to 90, find the maximum and minimum
f(x)=-cosx+cos(90°-x)
=sinx-cosx
=√￣2sin(x-45°)
∵0°
Y = cos (4-3x)
y‘=-sin(4-3x)*(-3)=3sin(4-3x)
Hope to help you
Help ∫ D / DX [x ^ Tan (x ^ 2)] DX and ∫ DX / (2 + 3x ^ 2)
∫d/dx[X^tan(x^2)]dx =∫d[X^tan(x^2)]=X^tan(x^2)+C∫dx/(2+3X^2) =(1/2)*∫dx/(1+(√(3/2)x)^2)=(1/2)*(√(2/3))∫d(√(3/2)x)/(1+(√(3/2)x)^2)=(√6/6)*arctan(√6x/2) +C (∫dx/(1+x^2)=arctanx+C)...
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