![](data:image/svg+xml;utf8,<svg xmlns="http://www.w3.org/2000/svg" xmlns:xlink="http://www.w3.org/1999/xlink" viewBox="0 0 72 71" width="72"></svg>)
A symmetry axis of the image with the function y = 1 / 2Sin (x / 2 + π / 8) is a straight line
The axis of symmetry of SiNx is the place where the most value is taken, that is, the maximum value or the minimum value
So x / 2 + π / 8 = k π + π / 2
x=2kπ+3π/4
The minimum positive period of the function y = sin (3x) is
sin^2(3x)=[1-cos(6x)]/2
The minimum positive period of COS (6x) is 2pi / 6 = pi / 3
So the answer is pi / 3
Simplify cos4x-4cos2x + 3
The answer is 8sin ^ 4x
cos4x=2cos^2(2x)
(cos2x-1)/2=-sin^2(x)
cos4x-4cos2x+3
=2cos^2(2x)-4cos2x+3
=2(cos^2(2x)-2cos2x+1)
=2(cos2x-1)^2
=8[(cos2x-1)/2]^2
=8[-sin^2(x)]^2
=8sin^4(x)
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