(1) If 3x-5 and 1-x are the square root of a number, then the value of X is 3 times of (2) x, and the difference between X and 2 is a non positive number, that is, the inequality is (3) The sum of squares of X and 4 is at least three times of X, that is, the inequality is

(1) If 3x-5 and 1-x are the square root of a number, then the value of X is 3 times of (2) x, and the difference between X and 2 is a non positive number, that is, the inequality is (3) The sum of squares of X and 4 is at least three times of X, that is, the inequality is

(1) If 3x-5 and 1-x are the square roots of a number, then the value of X is
3x-5+1-x=0
2x-4=0
x-2
(2)
The difference between 3 times of X and 2 is not positive, that is, the inequality is
3x-2≤0
(3)
The sum of squares of X and 4 is at least three times of X, that is, the inequality is
x²+4²≥3x
I've adopted this as well

The square root of a positive number is X-6 and 3x-2. Find the sum of X and the positive number

Given that rational numbers x and y satisfy x2 + Y2 + 4x-6y + 13 = 0, then YX = 0___ ．

∵ x2 + Y2 + 4x-6y + 13 = (x + 2) 2 + (Y-3) 2 = 0, ∵ x + 2 = 0, Y-3 = 0, that is, x = - 2, y = 3, then YX = 3-2 = 19

Given that the solutions of the equations ax − by = 42x + 3Y = 4 and ax + by = 24x − 3Y = 2 are the same, then a + B=______ ．

By solving the equations 2x + 3Y = 44x − 3Y = 2, we can get x = 1y = 23. By substituting the values of X and Y into ax by = 4, ax + by = 2, we can get the equations a − 23B = 4A + 23B = 2, we can get a = 3B = − 1.5, a + B = 3-1.5 = 1.5

Given that the solutions of {ax by = 4,2x + 3Y = 4 and {ax + by = 2,4x-3y = 4 are the same, then a + B =?

The solution should also satisfy the following equations:
2x+3y=4,4x-3y=4
So x = 4 / 3, y = 4 / 9
The equations are as follows
4a/3-4b/9=4
4a/3+4b/9=2
The solution is as follows
a=9/4
b=-9/4
So a + B = 0

The value of the integral (xsquare + ax-3y + 7) - (bxsquare-2x + 9y-1) has nothing to do with the value of the letter X. find the value of a and B

Solution
(x²+ax-3y+7)-(bx²-2x+9y-1)
=（1-b）x²+（a+2）x-12y+8=0
Because the value of the integral (xsquare + ax-3y + 7) - (bxsquare-2x + 9y-1) has nothing to do with the value of the letter X
So 1-B = 0, a + 2 = 0
So a = - 2, B = 1

Ask (x ^ 2-2x) - 11 (x ^ 2-2x) + 24, (2x + 3y-3) (2x + 3G + 7) - 11,4x ^ 2-12xy + 9y ^ 2-2x + 3y-6, x ^ 2 + 3ax-10a ^ 2-x + 2a,
Questioning
(x^2-2x)-11(x^2-2x)+24,(2x+3y-3)(2x+3G+7)-11,4x^2-12xy+9y^2-2x+3y-6,x^2+3ax-10a^2-x+2a,(x^2-7x+6)(x^2-x-6)+56,2x^2-3x-9,x^2+3x-(a^2+a-2),2(p+q)^2+6(p+q)+4,60x^2-60xy+15y^2-44x+22y+8,(x+1)(x+2)(x+3)(x+6)-3x^2,

1、(x^2-2x)²-11(x^2-2x)+24=（x²-2x-3）（x²-2x-8）=（x+1）（x-3）（x+2）（x-4）=（x+1）（x+2）（x-3）（x-4）2、(2x+3y-3)(2x+3y+7)-11=[(2x+3y)-3][(2x+3y)+7]-11=(2x+3y)+4(2x+3y)-32=(2x+3y-...

If (- ax-3y) (ax-3y) = the square of 49x + the square of 9y, find a

Because (- ax-3y) (ax-3y) = - (a ^ 2) x ^ 2 + 9y ^ 2
=49x ^ 2 + 9y ^ 2, so a ^ 2 = - 49 = 49i ^ 2
So a = - 7I or a = 7I (I is an imaginary unit)

Given 2x-3y = 5 2x + 3Y = 7, can you find ax & sup2; - 9y & sup2; in two different ways?
It should be to find the value of 4x & # 178; - 9y & # 178

2x-3y = 5. (1) formula 2x + 3Y = 7. (2) formula method 1: (1) * (2) = (2x-3y) * (2x + 3Y) = 4x & # 178; - 9y & # 178; = 5 * 7 = 35 method 2: (1) + (2): 4x = 12; X = 3 (2) - (1): 6y = 2; y = 1 / 3 take x, y into 4x & # 178; - 9y & # 178; formula 4 * 3 & # 178; - 9 (1 / 3) & # 178; = 4 * 9-1 = 35 method 3:

How to solve K square - 3K = 0

k(k-3)=0
k=3
k=0