When x is which integers, 2 ≤ 3x-7 < 8 holds?

When x is which integers, 2 ≤ 3x-7 < 8 holds?

According to the meaning of the question, we get 3x − 7 ≥ 2. ① 3x − 7 < 8. ②, from ①, we get x ≥ 3; from ②, we get x < 5. Then the solution set of the inequality system is 3 ≤ x < 5. So when x takes 3, 4, the inequality holds

The straight line y = KX + B passes through two points a (- 2, - 1) and B (- 3,0) to find the inequality 1 / 2x

By substituting a (- 2, - 1), B (- 3,0) into y = KX + B, we get the following result:
-2k+b=-1①
-3k+b=0②
From ① and ②, k = - 1, B = - 3
∴1/2x

As shown in the figure, the line y = KX + B (k < 0) intersects the X axis at the point (3, 0). The solution set of the inequality KX + b > 0 about X is ()
A. x＜3B. x＞3C. x＞0D. x＜0

The line y = KX + B (k < 0) intersects the X axis at the point (3, 0). When x = 3, y = 0, the function value y decreases with the increase of X. according to the fact that y decreases with the increase of X, the solution set of the inequality kx + b > 0 about X is x < 3

If the quadratic inequality KX + 2x-1 with respect to X

Question 1: KX + 2x-10 (X-2) (X-2) > 2, X is greater than 2 + radical 2 or X is less than 2-radical 2. ② function y = f (x) has zero point on [- 1,4], which is equivalent to equation x + ax + 2 = 0 on [- 1,4], and has solution equivalent to f (- 1) f (4)

As shown in the figure, the straight line y = KX + B passes through two points a (2,1), B (- 1, - 2) to find the solution set of the inequality - # 189; x > KX + b > - 2

The linear y = KX + B passes through a (2,1), B (- 1, - 2)
1=2k+b
-2=-k+b
The solution is: k = 1, B = - 1,
∴Y=X-1,
Inequality (x ＞ KX + B ＞ - 2) can be reduced to a system of inequalities
0.5X>X-1
X-1>-2
The solution is: - 1

It is known that the solution set of inequality 2x < KX + B < 0 is ()
A. x＜-2B. -2＜x＜-1C. -2＜x＜0D. -1＜x＜0

As shown in the figure, when - 2 ＜ x ＜ - 1, 2x ＜ KX + B ＜ 0 holds

As shown in the figure, if the line y = KX + B and the image y = 1 / 2x intersect at point a (2,1), then the solution set of inequality 1 / 2x > KX + B is?

A straight line y = KX + B, let y = 0 get x = B / K, which can be seen from the graph, 2

Point (x, y) satisfying function expression___ Points (x, y) on the graph of the function_____ On the graph of the function

Sure, sure

Find the area enclosed by the function image determined by the equation | X-1 | + | y + 2 | = 2
|This is an absolute value

In fact, this is the intersection of two groups of mutually perpendicular parallel lines, and then calculate the area of the part surrounded by them
The four linear equations are as follows:
x+y=1
x-y=1
x+y=-3
x-y=5
It is easy to get that the length of the side surrounded by four straight lines is 2 √ 2, and it is a square with an area of 8

If the power function f (x) and G (x) pass through (3,9) (8,32) respectively, then the inequality f (x) ≥ g (x) solution set

If the images of power functions f (x) and G (x) pass through points (3,9) (8,32) respectively, f (x) = x ^ 2 and G (x) = x ^ (5 / 3), then the solution set of x ^ 2 > = x ^ (5 / 3) is (- ∞, 0] u [1, + ∞]