It is known that y is the inverse proportional function of X. when x = 3, y = 2. Then the analytic expression of the function of Y and X is? And the value range of the independent variable x is?
It is known that y is the inverse proportional function of X. when x = 3, y = 2
Then the analytic expression of Y and X is y = 6 / X
The value range of independent variable x is any real number with X ≠ 0
How to find the value range of the independent variable of the inverse proportion function?
Given that the voltage u at both ends of the lamp is 220 V, the resistance of the tungsten wire in the bulb is r, and the current intensity is I
1. Find the analytic expression of I with respect to R and the value range of independent variable R
I=U/R
I=220/R
The value is r > 0
What is the value range of the independent variable x in the inverse scale function
That's x ≠ 0
Given that P (2,2) is on the image of inverse scale function y = K / X (K ≠ 0), if the value range of function y is y ≥ 3, then the value range of independent variable x is?
A:
The point P (2,2) is substituted into the inverse proportional function y = K / X to obtain:
2=k/2
k=4
So: y = K / x = 4 / x > = 3
So: 0
If P (2,1) is a point on an image with inverse scale function y = K / x, then
k=2*1=2
y2
The other part is X
In the function y = 2x-1 / 1, the value range of the independent variable x is?
X is not equal to 2 / 1
The value range of the independent variable X of the function y = 2x + 1 / X-1 is
2x+1≠0
X ≠ = - 1 / 2
The value range of independent variable X of function y = 5 / 2x-1
Y = 5 / 2x-1
The denominator must be 2x-1 ≠ 0
Then: X ≠ 1 / 2
Therefore, the value range of X is {x | x ∈ R. and X ≠ 1 / 2}
The value range of independent variable of y = 2x-1 function
The value range of the independent variable is that x is all real numbers
That is, X ∈ (- ∞, + ∞)
The value range of function independent variable is the value range of those that make sense of
Is the value of the independent variable X that makes the function meaningful