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3x^2-1-2x-5+3x-x^2
3x²-1-2x-5+3x-x²
=（3-1）x² + （3-2）x -1 -5
= 2x²+ x -6
M = 3x's square + 2x-1 n = - X's Square - 2 + 3x
M = 3x squared + 2x-1; 2n = - 2x squared - 4 + 6x;
M-2n = the square of 5x-4x + 3
Solving equation (3x / 2x-1) ^ 2-2 (3x / 2x-1) - 3 = 0
[3x/(2x-1)]²-2[3x/(2x-1)] -3=0
[3x/(2x-1) -3][3x/(2x-1) +1]=0
3x / (2x-1) = 3 or 3x / (2x-1) = - 1
3x = 3 or 5x = 1
If x = 1 or x = 1 / 5 is substituted into the fractional equation test, the denominator is not equal to 0, and both solutions are solutions of the equation
X = 1 or x = 1 / 5
Solving the equation 2x ^ 2 + 3x = 0
emergency
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