5.6 + 2x = 11.6-3x, find X

5.6 + 2x = 11.6-3x, find X


5.6+2X=11.6-3X
2x+3x=11.6-5.6
5x=6
x=1.2



{3x-2 > x + 6 / 2 X-5 < 5-2x


3x-2>x+6
2x>8
x>4
X-5 < 5-2x
x-5<10-4x
5x<15
x<3
So 4 < x < 3



To find the maximum value of 3x (16-x) (20-2x), we need to explain the principle, that is, we use the condition of equal sign of mean inequality


By ABC ≤ [(a + B + C) / 3] ^ 3
3x(16-x)(20-2x)≤[(3x+16-x+20-x)/3]^3=1728
When 3x = 16-x = 20-2x, i.e. x = 4, the original formula has a maximum value of 1728