Factorization of (A & sup2; - a) - (A-1) & sup2, And (5a-4b) & sup2; - 2 (5a-4b) (3a-2b) - (- A + 2b) (- a-2b) Where a = - 1, B = 2 It is known that X-Y = - 1, xy = 3, find the quartic power of 2x, Y & sup2; + 2x & sup2; y

Factorization of (A & sup2; - a) - (A-1) & sup2, And (5a-4b) & sup2; - 2 (5a-4b) (3a-2b) - (- A + 2b) (- a-2b) Where a = - 1, B = 2 It is known that X-Y = - 1, xy = 3, find the quartic power of 2x, Y & sup2; + 2x & sup2; y

Given that SiNx is equal to negative half, find X

210 degrees + 2K degrees

Factorization: A ^ 2 + B ^ 2-2ab-c ^ 2

Original formula:
= a^2-2ab+b^2-c^2
= (a-b)^2-c^2
=(a-b+c)(a-b-c)

If | SiNx | = SiNx, then the set of angles x is
(2) If | CTG x | = - ctgx, then the set of angles x is?

(1) The problem turns into SiNx > = 0, that is 2K

Factorization C ^ 2 - 1 + 2Ab - A ^ 2 B ^ 2

c^2 - 1+ 2ab - a^2 b^2
=c²-(1-2ab+a²b²)
=c²-(1-ab)²
=(c+1-ab)(c-1+ab)

Finding a ∩ B with known set a = {x | SiNx ≥ 0} B = {x | 6 ≤ x ≤ 6}
Finding a ∩ B with known set a = {x | SiNx ≥ 0} B = {x | - 6 ≤ x ≤ 6}

[-6,-π]∪[0,π]

Factorization of 1-A ^ 2-B ^ 2 + 2Ab

= 1 - (a^2 + b^2 - 2 a b)
= 1 - (a - b)^2
= [1 + (a - b)] [1 - (a - b)]
= ( 1 + a - b) (1 - a + b)

Given the set P = {x │ - 2 ≤ x ≤ 5}, q = {x │ M-1 ≤ x ≤ 2m-1}
1. If 3 ∈ Q and 5 ∈ Q, find the value range of M;
2. If q is a subset of P, find the value range of M

1. Substituting x = 3 into set Q, we get 2 ≤ m ≤ 4
Substituting x = 5 into set Q, we get 3 ≤ m ≤ 6
If 5 is not ∈ Q, then M is 2 ≤ m < 3
2. If q is a subset of P, then - 2 ≤ M-1 ≤ 5, - 2 ≤ 2m-1 ≤ 5
Solution inequality take intersection OK!

Factorization 2ab-a ^ 2-B ^ 2 + 1
Fast

2ab-a^2-b^2+1
=1-(a^2-2ab+b^2)
=1^2-(a-b)^2
=(1+a-b)(1-a+b)

Given the set s = {x | 1 ＜ x ≤ 7}, a = {x | 2 ≤ x ＜ 5}, B = {x | 3 ≤ x ＜ 7}
1.（CsA)∩(CsB)
2.Cs(A∪B)
3.（CsA)∪(CsB)
4.Cs(A∩B)

1.{x|1＜x＜2}
2.{x|1＜x＜2}
3. {x | 1 ＜ x ＜ 3 or 5 ≤ x ≤ 7}
4. {x | 1 ＜ x ＜ 3 or 5 ≤ x ≤ 7}
I won't use the formula on the first floor, but it's obvious to draw a Wayne diagram on the number axis! Come on!