How to do the factorization of the fifth power of a minus 16 A and the third power of a minus 36 A?

How to do the factorization of the fifth power of a minus 16 A and the third power of a minus 36 A?

a^5-16a^3-36a
=a(a^4-16a^2-36)
=a(a^2+2)(a^2-18)
In the range of rational numbers, factorization stops here. In the range of real numbers, factorization stops here
=a(a^2+2)(a+3√2)(a-3√2)

Factorization of a ^ 5-9
Try not to use decimals

(a^(5/2)+3)(a^(5/2)-3)

Calculation: 3 (a-b) 2 · [9 (a-b) n + 2] · (B-A) 5=______ ．

The original formula = 3 (a-b) 2 · [9 (a-b) n + 2] · [- (a-b) 5] = - 27 (a-b) 2 + N + 2 + 5 = - 27 (a-b) n + 9, so the answer is: - 27 (a-b) n + 9