The position of rational number a, B and C on the number axis is shown in the figure to find | a + B | + | B + C | - | 2b-a| The number axis looks like this ——B -- C -------- 0 -------- a -------- X this is the positive direction

The position of rational number a, B and C on the number axis is shown in the figure to find | a + B | + | B + C | - | 2b-a| The number axis looks like this ——B -- C -------- 0 -------- a -------- X this is the positive direction

-2a-c

The positions of rational numbers a, B, C on the number axis are shown in the figure below. Try to simplify a + C - c-2b + A + 2B + | B + C|
The first one on the left is B, the second is a, the third is 0, and the fourth is C

I'll tell you a method. This kind of problem uses the fixed value method, because it only uses graphs, which is abstract and difficult to judge
Let B = - 2, a = - 1, C = 1
The method is given to you, and the answer is calculated by yourself. The method is more important than the answer

(radical Mn - M / N of radical) / / M / N of radical
(n>0)

(radical Mn - M / N of radical) / / M / N of radical
=Radical (Mn * n / M) - radical (M / N * n / M)
=Radical (n & # 178;) - 1
=n-1

(a ^ 2 radical n / M-M AB radical Mn + m radical n / N) divided by (a ^ 2B ^ 2 radical n / M)

[a ^ 2 radical (n / M) - AB radical (MN) / M + n radical (M / N) / M] / [a ^ 2B ^ 2 radical (n / M)]
=[a ^ 2 radical (MN) / M - AB radical (MN) / M + radical (MN) / M] / [a ^ 2B ^ 2 radical (MN) / M]
=[a ^ 2 radical (MN) - AB radical (MN) + radical (MN)] / [a ^ 2B ^ 2 radical (MN)]
=( a^2 - ab + 1) / (a^2b^2)