The solution equation (1) a / (x-a) B = 1 (B is not equal to 1) (2) m / x-n / (x 1) = 0 (M is not equal to N, Mn is not equal to 0)

The solution equation (1) a / (x-a) B = 1 (B is not equal to 1) (2) m / x-n / (x 1) = 0 (M is not equal to N, Mn is not equal to 0)

（1）a/（x-a）+b=1
a/（x-a）=1-b
x-a = a/(1-b)
x = a+a/(1-b) = a{(1+1/(1-b)} = a(2-b)/(1-b)
（2）m/x-n/(x+1)=0
m/x=n/(x+1)
[m(x+1)]/[x(x+1)]=(nx)/[x(x+1)]
m(x+1)=nx
mx+m=nx
mx-nx=m
(m-n)x=m
∵m≠n
∴m-n≠0
∴x=m/(m-n)

Mathematics fraction equation 2000 / x = 6300 / (1 + 5%) x

2000/x=6300x/（1+5%)
2000/x=6000x
1/x=3x
1=3x^2
x^2=1/3
The solution is: x = ± √ (1 / 3)
x=±√3/3
Substituting x = ± √ 3 / 3 into the simplest denominator x ≠ 0 is the solution of the original equation
So the solution of the original equation is: x = ± √ 3 / 3

How to solve the fractional equation
X + 1 / x equals 3 times the sum of brackets x + 1 / 2x, then add 1
x/x+1=[2x/3(x+1)]+1

To get the denominator: 3x = 2x + 3 (x + 1)
To get rid of brackets: 3x = 2x + 3x + 3
The result is: 3x -- 2x -- 3x = 3
Merge the similar items to get: - - 2x = 3
The coefficient is 1: x = -- 3 / 2
The test shows that x = -- 3 / 2 is the solution of the original fractional equation