Algorithm of 1 / 2 × 2 / 3 × 3 / 4 × 4 / 5 × 5 / 6 ×. × 47 / 48 × 48 / 49 × 49 / 50 It's all right

Algorithm of 1 / 2 × 2 / 3 × 3 / 4 × 4 / 5 × 5 / 6 ×. × 47 / 48 × 48 / 49 × 49 / 50 It's all right

=1/50
You see / 2 and * 2 disappear
3, too
4, too
Until 49
is it?
Here you are
XD

50-49 + 48-47 + 46-45.4-3 + 2-1

If there are two adjacent numbers, the even number minus the odd number in front of it will always be 1, so the result is 50 / 2 = 25

Simple algorithm (1 * 2) / 1 + (2 * 3) / 1 + (3 * 4) / 1. (49 * 50) / 1 (must be simple)

(1*2)/1+(2*3)/1+(3*4)/1.(49*50)/1
=1-1/2+1/2-1/3+1/3-1/4+...-1/49+1/50
=1-1/50=49/50

Simple calculation of (7 / 8 + 3 / 16) △ 13 / 16

(7/8+3/16)÷13/16
=(14/16+3/16)×16/13
=17/16×16/13
=17/13